Find the electric field (magnitude and direction) at the location of qa in the figure below, given that q, = 10.70 µC and q. = -5.90 µC. Point charges located at the corners of an equilateral triangle 22.0 cm on a side. Magnitude |E| = direction (wrt +x-axis) = Submit Answer Incompatible units. No conversion found between "uc" and the required units. O Tries 0/10 Previous Tries What is the force (magnitude and direction) on qa, given that qa = 1.40 nC. Magnitude |F| = direction (wrt +x-axis) = Submit Answer Tries 0/10

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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Find the electric field (magnitude and direction) at the location of qa in the figure below, given that qp = 10.70 µC and qc
= -5.90 µC. Point charges located at the corners of an equilateral triangle 22.0 cm
on a side.
qa
Magnitude |E|
direction (wrt +x-axis)
Submit Answer
Incompatible units. No conversion found between "uc" and the required units. O
Tries 0/10 Previous Tries
What is the force (magnitude and direction) on qa, given that qa = 1.40 nC.
Magnitude |F|
direction (wrt +x-axis)
Submit Answer
Tries 0/10
Transcribed Image Text:Find the electric field (magnitude and direction) at the location of qa in the figure below, given that qp = 10.70 µC and qc = -5.90 µC. Point charges located at the corners of an equilateral triangle 22.0 cm on a side. qa Magnitude |E| direction (wrt +x-axis) Submit Answer Incompatible units. No conversion found between "uc" and the required units. O Tries 0/10 Previous Tries What is the force (magnitude and direction) on qa, given that qa = 1.40 nC. Magnitude |F| direction (wrt +x-axis) Submit Answer Tries 0/10
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