A particle of mass 6.6 x 10 kg and charge +9.0 µC is traveling due east. It enters perpendicularly a magnetic field whose magnitude is 4.5 T. After entering the field, the particle completes one-half of a circle and exits the field traveling due west. How much time does the particle spend in the magnetic field? Number Units
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- A particle of charge = +7.9 nC and mass = 5 micro-gram) moves with a velocity V = 8.8 i km/s in a region where the magnetic field is B = 6.8 j+ 7 k mī. What is the magnitude of the force on the particle due to the magnetic field? Write your answer in nano-newtons.In a mass spectrometer, a beam of protons enters a magnetic field. Some protons make exactly a one-quarter circular arc of radius 0.50 m. a) If the field is always perpendicular to the proton's velocity, what is the field's magnitude if exiting protons have a kinetic energy of 10. keV? b) How long does it take the proton to complete the quarter circle? c) Find the net force (magnitude) on a proton while it is in the field.An electron moves in a circular path with a speed of 1.22 x 10' m/s in the presence of a uniform magnetic field with a magnitude of 2.12 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution? S
- The magnetic field in a hospital’s cyclotron is 0.170 T. Find the magnitude of the magnetic force on a proton with speed 2.60 × 107 m/s moving in a plane perpendicular to the field. answer in NYou have placed electrons in a magnetic field. The electrons move in horizontal circles of radius 9.5 cm when their speed is 2.0×10^6 m/s. What is the magnitude and direction of the magnetic field that causes this motion?A proton experiences the greatest force as it travels 2.9 x 106 m/s in a magnetic field when it is moving northward. The force is upward and of magnitude 7.2 x10-13 N. What is the magnitude and direction of the magnetic field?
- A magnetic field has a magnitude of 0.0014 T, and an electric field has a magnitude of 3.5 × 103 N/C. Both fields point in the same direction. A positive 1.7-μC charge moves at a speed of 2.8 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number 1+1 P90⁰ Units BAA proton moves with a speed of 963953 m/s. It is travelling in the xy plane. A magnetic field of 7.3 mT is pointing in the z-direction. What is the radius (in meters) of the circular path this electron will follow?A proton moving in the positive y direction perpendicular to a magnetic field experiences a force due to a magnetic field in the positive x direction. What is the direction of the magnetic field over this region? draw a diagram showing the moving particle, the magnetic field, and the path of the proton in the field as it is deflected by the magnetic field
- An electron moves in a uniform circular motion under the action of an external magnetic field. -19 Consider the charge of the electron 9 = -1.6 × 10- v = 2.8 X 107 [C], the speed of the electron B = 2.1 x 10-³ [m/s] and the magnitude of the external magnetic field [T]. Calculate the radius R of the circle formed by the electron during its displacement. Write your answer in centimeters and round to the first decimal.An electron moves in a circular path with a speed of 1.36 x 107 m/s in the presence of a uniform magnetic field with a magnitude of 1.84 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution? S Read It