A particle of mass 5.7 x 10 kg and charge +8.9 µC is traveling due east. It enters perpendicularly a magnetic field whose magnitude is 4.1 T. After entering the field, the particle completes one-half of a circle and exits the field traveling due west. How much time does the particle spend in the magnetic field? Number Units
Q: A 5 T uniform magnetic field is oriented horizontally with respect to this page. A 3.0×10^ -6 C…
A: Field, B = 5 T Charge, q = 3×10-6 C Velocity, v = 1000 m/s Angle between field and velocity, θ = 90°
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A: when a proton enters a magnetic field and it travels perpendicular to the magnetic field then it…
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A: Time period of circular motion is given by: T = (2*pi)/w = (2*pi)/(V/R) = 2*pi*R/V Now Using force…
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A: Given Data:- Mass of the particle is m=8.3×10-8 kg. Charge of the particle is q=+7.3 μC =+7.3…
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Q: In the figure, four long straight wires are perpendicular to the page, and their cross sections form…
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