BiologyA partial amino acid sequence from thetick anti-coagulant protein is:Tyr-Met-Ser-Arg-Phe-Val-Tyr-Lys-His-Cys-Met-Leu-lle-Arg-Thr-Pro......You wish to make a set of DNAprobes to screen your tick library for theclones containing the sequence thatencodes this protein. Your probesshould be 15 nucleotides in length.Which amino acids in the proteinshould be used to construct the probesso that the least degeneracy results(consult the genetic code)? How manydifferent probes must be synthesized tobe certain that you will find the correctsequence that specifies the protein?Give the nucleotide sequence of anyone of these probes.

The genetic code is a set of three-letter combinations of nucleotides called codons that corresponds…

Answered: A partial amino acid sequence from the…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Similar questions

Describe the outcome of a chain-terminator sequencing procedure in which (a) too little ddNTP is added or (b) too much ddNTP is added.
You have the following DNA sequence: 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G that is underlined changes to to a C the result will be - A) A nonsenese mutation B) A frameshift mutation C) A silent substitution D) A missense mutation You have the following DNA sequence: 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G that is underlined is deleted, then the result will be A) A nonsense mutation B) A frameshift mutation C) A silent substitution D) A missense mutatio If there are 3000 bases in the coding region of a gene, the gene will have A) 3000 amino acids B) 6000 amino acids C) 1000 amino acids D) 3000 codons
A gene contains the sequence CGCATACGGTAC that results in the amino acid sequence arg-ile-arg- tyr. A mutation in this gene has a G inserted after the second C in the strand. How will this mutation affect the phenotype? A:This will affect the phenotype because although most of the protein will be identical, the first amino acid will be different. B:This will not affect the phenotype because only the second amino acid is different from the original protein. C:This will not affect the phenotype because the protein will be identical to the original protein. D:This will affect the phenotvpe because all of the amino acids after the first one will be different from he original protein.
The genetic alteration responsible for sickle-cell anemia in humans involves: a transition mutation from A to G, substituting glutamic acid for valine in a-globin a transversion mutation from T to A, substituting valine for glutamic acid in b-globin a transition mutation from T to C, substituting valine for glutamic acid in b-globin a transversion mutation from G to C, substituting glutamic acid for valine in a-globin a frameshift mutation of one ATC codon, removing glutamic acid from b-globin
The words at the bottom with commas are the answer choices or word bank
Which primer would bind to this coding strand as a reverse primer? 5'- ATGGCCAAAT GATTCCCACG ATTTGGCCAT TGAGATCCGG - 3' O3'- ATGGCCAAAT - 5' O 5'- CCGGATCTCA - 3' O 5'- ATGCGCAGAT - 3' O3'- CCGGATCTCA - 5' N
In Sickle Cell Disease, the 6th amino acid after the START codon is different than it is in wildtype hemoglobin. An alignment of HbA DNA (wt) against HbS (sickle allele) is shown below. Arcel is asked to characterize the DNA mutation according to its nucleotide and position. r + 2 HbA: ATG HbS: GTG CAC CTG ACT CCT GAG CAC CAC CTG ACT ACT CCT GTG Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. ATG GTG The disease is caused by A20 - T20. The disease is caused by T20 - A20. The disease is caused by GAG20 - GTG20. The disease is caused by GTG21 - GAG21 ☐
Damien and Jessica are friends that are interested in proteomics. One day Damien and Jessica go to a proteomics lab to have their proteome (all proteins in body) analyzed. The analysis shows that there is a difference in one amino acid within each of their hemoglobin proteins. However, both of their hemoglobin proteins appear to be functioning properly. They both come to you and ask you the significance of this finding, what do you tell them? Should they be worried? Provide a detailed rationale. .
People who carry a theoretical genetic disorder (called B-disease) can be identified from a 2kb DNA sequence.People who carry this genetic disorder have a single nucleotide polymorphism that results in a change of GTATTC to GGATTC, a site that only occurs once at nucleotide number 750 in this DNA sequence. Answer the following questions based on the information provided. (a) How can you develop a simple molecular test to identify the genetic disorder? (b) If you have carried out the molecular test (based on the information above) on a 100 individual and found that 24 were healthy (BB) and 26 were carriers (bb); 1) What is the ratio of heterozygous? 2) Show how can you identify the three types from the agarose gel
You have the following DNA coding sequence of a wild-type allele: 5’-ATG TTC CAG CTA GAT GAT ATG CTG GTA ATT GGG GAA CGC GCG CGG TAA-3’ For each of the following mutations: A. State whether the mutation is missense, nonsense, frameshift, or silent. B. Write the codon change that occurs for the missense, nonsense, and silent mutations (ex. GAA -- GAT). C. For frameshift mutations, write out the entire mutant sequence with each codon clearly indicated (if the frameshift creates a new stop codon, end the sequence at the new stop). Using the wild type DNA sequence above as a guide : Write the amino acid sequence of the mutants. Mutant 1: transition at nucleotide 23 Mutant 2: T --> G transversion at nucleotide 29 Mutant 3: an insertion of “A” after nucleotide 14 Mutant 4: transition at nucleotide 7 Mutant 5: An insertion of GG after nucleotide 40 Mutant 6: transition at nucleotide 15 Mutant 7: a deletion of nucleotide 25
You isolate a mouse Tau-gene-containing DNA fragment from the chicken and hybridize it to the freshly-made and isolated hnRNA (primary transcript) from the nucleus of the mouse cells transcribed from the Tau gene (immediately after it was produced), allowing no time for processing of the hnRNA. Describe what you see when you look at the DNA/RNA hybrid molecule under the electron microscope.
Consider the expression “central dogma,” which refers to the flow of genetic information from DNA to RNA to protein. is the word “dogma” appropriate in this context?

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