A parallel-plate capacitor has the capacitance of C = 10 µF when the distance of thetwo plates is d = 5 cm. A battery with the emf = 3 V is used to charge the capacitor.%3D1. How much charge can be put on the parallel-plate capacitor? (in the unit of pC)Q =Submit AnswerTries 0/2Now, consider the following two cases separately:Case 1: if the emf stays connected, but the distance of the parallel plates is changedto d = 80 cm.2. What is the new capacitance C1 and how much is the charge Q1in the capacitor?C1 =µF%DQ1 =%3DSubmit AnswerTries 0/2Case 2: After the initial charging, the emf is removed. Therefore, the amount ofcharge you calculated from the question #1 remains in the capacitor. Now, again, thedistance of the parallel plates is changed to d1 = 80 cm.3. What is the potential difference V1 across the capacitor?V1 =%3D

Given data, capacitance, C1 = 10 μF distance between the 2 plates, d = 5 cm potential difference…

A parallel-plate capacitor has the capacitance of C1 = 10 pF when the distance of the two plates is d = 5 cm. A battery with the emf = 3 V is used to charge the capacitor. %3D %3D 1. How much charge can be put on the parallel-plate capacitor? (in the unit of pC) Q = Submit Answer Tries 0/2 Now, consider the following two cases separately: Case 1: if the emf stays connected, but the distance of the parallel plates is changed to di = 80 cm. 2. What is the new capacitance C1 and how much is the charge Qiin the capacitor? C1 = Q1 = µF Submit Answer Tries 0/2 Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in the capacitor. Now, again, the distance of the parallel plates is changed to di 3. What is the potential difference V1 across the capacitor? 80 cm.

A parallel-plate capacitor has the capacitance of C1 = 10 pF when the distance of the two plates is d = 5 cm. A battery with the emf = 3 V is used to charge the capacitor. %3D %3D 1. How much charge can be put on the parallel-plate capacitor? (in the unit of pC) Q = Submit Answer Tries 0/2 Now, consider the following two cases separately: Case 1: if the emf stays connected, but the distance of the parallel plates is changed to di = 80 cm. 2. What is the new capacitance C1 and how much is the charge Qiin the capacitor? C1 = Q1 = µF Submit Answer Tries 0/2 Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in the capacitor. Now, again, the distance of the parallel plates is changed to di 3. What is the potential difference V1 across the capacitor? 80 cm.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Q3. The plates of an air-filled parallel-plate capacitor with a plate area of 16.0 cm² and a…

A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

Q: Part A What is the charge on the capacitor? Express your answer using two significant figures. ? Q -…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: Q20. An open tub rolls across a frictionless surface. As it rolls, rain falls vertically into the…

A: Given:: Quantitative explaination

Q: A 2.6-cm-diameter parallel-plate capacitor has a 1.8 mm spacing. The electric field strength inside…

Q: The plates of a parallel-plate capacitor are 3.28 mm apart, and each has an area of 9.72 cm². Each…

A: Given that, The separation between the parallel plate capacitor, d=3.28 mm=3.28×10-3 m Plate area,…

Q: A charged particle of mass 1 microgram and charge 10 nC with velocity 2,000 m/s enters the center of…

A: Solution:-

Q: A conducting sphere of radius R = 16.0 m has a net charge Q = 7.00x10-6C. What is the potential %3D…

A: Given:- A conducting sphere of the radius R=16.0 m Net charge Q=7.00×10-6 C Point A is 20.0 m of the…

Q: The capacitors of C₁ = 2 µF and C₂ = 3 µF are each fully charged with potential difference of 30 V.…

A: C1= 2µF C2= 3µF Potential difference is =30 V

Q: A parallel-plate capacitor is constructed from two square sheets of aluminum foil, each of…

Q: Two square parallel plates with a separation of d = 1.5 mm are charged up with charges of equal…

Q: What is the capacitance of a parallel plate capacitor with metal plates. each plate has an area of…

A: formula required is as follows;

Q: A parallel plate capacitor has square plates 6cm on a side, separated by 0.3mm. The capacitor is…

Q: P 2: An air-filled parallel plate capacitor of gap d is connected to a battery until fully charged.…

Q: A capacitor consists of square conducting plates 24 cm on a side and 4.0 mm apart, carrying charges…

A: (A) The required electric field be calculated as,

Q: A parallel plate capacitor in air is constructed with two 32 cm x 32 cm square conductors separated…

A: dimensions of square plate = 32 cm × 32 cm separation between the plates (d) = 4 mm

Q: I need help with Part A and Part B because I don't know how to do this problem

Q: 2 of 7 826 words A certain parallel-plate capacitor has two 3.5 cm-diameter-disks spaced 2.8 mm…

Q: In (Figure 1), AV = 11 V. Figure AV C₁ = 16 µF HH =C₂=40 μF =C3= 60 μF What is the charge on each…

A: Given Data: Voltage (V) = 11 V.Capacitor 1 (C1) = 16 μF.Capacitor 2 (C2) = 40 μF.Capacitor 3 (C3) =…

Q: A parallel-plate capacitor has plates with an area of 420 cm² and an air-filled gap between the…

Q: In (Figure 1), let C₁ = 2.90 μF, C₂ = 5.10 μF, and Vab = +60.0 V. Figure A Vab= V b gra +0. 1 of 1 T…

Q: An air-filled parallel-plate capacitor has plates of area 2.90 cm² separated by 2.30 mm. The…

Q: A 15.0 µF capacitor is charged to a potential difference of 850.0 V. The terminals of the charged…

A: The first capacitor is initially charged to a potential difference of 850 V Let C1=15 μF=15×10-6…

Q: A 0.8 µF capacitor is charged to a potential difference of 12.0 V. The wires connecting the…

Q: A certain capacitor holds a charge of 94 nC when a voltage of 24 V is applied to it. a. What is the…

Q: A homemade capacitor is assembled by placing two 8-in. pie pans 6 cm apart and connecting them to…

Q: A parallel-plate capacitor is constructed with circular plates of radius 5.10x10-2 m . The plates…

Q: A parallel plate capacitor is constructed using plates of area A and a spacing between the plates d…

A: The capacitance of a parallel plate capacitor is given by the formula: C=εAd where C is the…

Q: When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane…

A: Given, Electric Field in one direction = 7×105 N/C Electric Field in another direction = 3.1× 105…

Q: 2. In lecture we saw parallel plate and coaxial cylindrical capacitors. We can also have spherical…

Concept explainers

Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

A parallel-plate capacitor has the capacitance of C = 10 µF when the distance of the
two plates is d = 5 cm. A battery with the emf = 3 V is used to charge the capacitor.
%3D
1. How much charge can be put on the parallel-plate capacitor? (in the unit of pC)
Q =
Submit Answer
Tries 0/2
Now, consider the following two cases separately:
Case 1: if the emf stays connected, but the distance of the parallel plates is changed
to d = 80 cm.
2. What is the new capacitance C1 and how much is the charge Q1in the capacitor?
C1 =
µF
%D
Q1 =
%3D
Submit Answer
Tries 0/2
Case 2: After the initial charging, the emf is removed. Therefore, the amount of
charge you calculated from the question #1 remains in the capacitor. Now, again, the
distance of the parallel plates is changed to d1 = 80 cm.
3. What is the potential difference V1 across the capacitor?
V1 =
%3D

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

In (Figure 1), AV = 13 V. Figure + AV C₁ = 16 μF HH =C₂ = 40 μF =C3= 60 μF 1 of 1 Part A What is the charge on each capacitor? Enter your answers in microcoulombs separated by commas. Q₁, Q2, Q3 = Submit Part B 197| ΑΣΦ Submit Request Answer AV₁, AV₂, AV3 = Provide Feedback What is the potential difference across each capacitor in the figure? Enter your answers in volts separated by commas. 17 ΑΣΦ pas Request Answer ? By ? μC V
A parallel plate capacitor is designed as shown in Fig.The capacitor has a cross-sectional area of A = (1,2 × 1,2) cm2, the distance between the plates d= 2 mm, where the dielectric constant k1 = 4, k2 = 6, and k3 = 2.a. Describe the capacitor combination (series, parallel) formed byall three dielectric materials.b. Calculate the total capacitance of the capacitor?c. If the capacitor is connected with a potential difference V = 5 voltsthen determine the charge and energy stored in the capacitorthe?
Three capacitors are connected as shown, where C = 0.045 F. A. Input an expression for the equivalent capacitance between points a and b, in terms of C. B. What is the capacitance, in farads? C. If the capacitors are charged with a ΔV = 10 V source, how much energy will the circuit store, in joules?
What potential difference is needed to accelerate an electron from rest to a speed of 1.2x106 m/s? Express your answer to two significant figures and include the appropriate units. μÅ AV= Value Submit Request Answer Ć Units ?
Part a through c please In the figure (Figure 1), C1= C5= 8.8 μF and C2= C3= C4= 4.0 μF. The applied potential is Vab= 230 V. Part A What is the equivalent capacitance of the network between points a and b? Express your answer using two significant figures. Part B What is the charge of C1, C2, C3, C4, C5 Part C What is the potential differences of C1, C2, C3, C4, C5
A parallel plate capacitor in air is constructed with two 13 cm x 13 cm square conductors separated by 3 mm. a) Determine the value of the capacitance of this parallel plate capacitor. b) This capacitor is placed across a 12 V battery and allowed to fully charge. What is the value of this charge? To continue, please enter your answer in b) in units of nC. Round your answer to 1 decimal place.
In Lab 3, we measured the dielectric constant of glass using a parallel plate capacitor. Suppose that a piece of flat glass panel with a linear dielectric constant ɛ, = 2.5 is inserted between the plates of such a capacitor. The thickness of the glass is d = 5mm. The glass is in contact with both plates. One of the plates of the capacitor is kept at +3V, and the other plate is grounded. Treat the plates as infinitely large and thus the electric field is uniform between the plates. a) Calculate the electric field between the plates. b) Calculate the (uniform) polarization created in the glass. c) Calculate the surface bound charge density on the side of the glass that is in contact with the positive plate of the capacitor. d) Calculate the electric displacement between the plates. e) Calculate the free charge per unit area on the positive plate of the capacitor.
Suppose in the figure(Figure 1) that C1=C2=C3=40.9μFC1=C2=C3=40.9μF and C4=71.2μFC4=71.2μF. a.If the charge on C2C2 is Q2=20.7μCQ2=20.7μC, determine the charge on each of the other capacitors. Enter your answers numerically separated by commas. Determine the voltage across each capacitor. Enter your answers numerically separated by commas. Determine the voltage Vabacross the entire combination.
A coaxial cylindrical cable has an inner conductor of radius a = 0.0034 m, a surrounding conductor of radius b = 0.013 m, and length l = 2.8 m. a. Calculate the numerical value of the capacitance in F. b. Express the capacitance C through potential difference across the capacitor ΔV and charge Q. c. If the potential difference ΔV = 0.3 V, how much charge is stored in the capacitor?
Two 2.50 cm x 2.50 cm square aluminum electrodes are spaced 0.530 mm apart. The electrodes are connected to a 140 V battery. Part A What is the capacitance? Give your answer in picofarads. (pico = 10-12) ? C = 1.044 pF Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the charge on each electrode? Give your answer in nanocoulombs. Ηνα ΑΣφ x•10" Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining