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(a) Option 1:- Given that the precision temperature sensor produces an output voltage (Vs: sensor output voltage) according to the equation Vs= (11.69mV) T°C +1.8663 V. This equation can be expressed in terms of temperature (T) versus sensor voltage (Vs). ie. T=(Vs-1.8663) / (0.01169) You are to design the amplifier circuit for this sensor using any combination of inverting amplifiers, non-inverting amplifiers, summing amplifiers (No need to use all types of amplifier) together with a 1V reference voltage source. The sensor voltage (Vs) and a 1V reference source (Vref) are the two input signal of your circuit. Your designed circuit should produce an output voltage (V.) to indicate the temperature according to the equation Vo = T/10. (°C/10) i.e When T=0 °C, Vo = OV and T = 100 °C, Vo = 10V.

(a) Option 1:- Given that the precision temperature sensor produces an output voltage (Vs: sensor output voltage) according to the equation Vs= (11.69mV) T°C +1.8663 V. This equation can be expressed in terms of temperature (T) versus sensor voltage (Vs). ie. T=(Vs-1.8663) / (0.01169) You are to design the amplifier circuit for this sensor using any combination of inverting amplifiers, non-inverting amplifiers, summing amplifiers (No need to use all types of amplifier) together with a 1V reference voltage source. The sensor voltage (Vs) and a 1V reference source (Vref) are the two input signal of your circuit. Your designed circuit should produce an output voltage (V.) to indicate the temperature according to the equation Vo = T/10. (°C/10) i.e When T=0 °C, Vo = OV and T = 100 °C, Vo = 10V.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Official (Closed) - Non Sensitive (a) Option 1:- Given that the precision temperature sensor produces an output voltage (Vs: sensor output voltage) according to the equation Vs= (11.69mV) T °C +1.8663 V. This equation can be expressed in terms of temperature (T) versus sensor voltage (Vs). ie. T = (Vs-1.8663) / (0.01169) You are to design the amplifier circuit for this sensor using any combination of inverting amplifiers, non-inverting amplifiers, summing amplifiers (No need to use all types of amplifier) together with a 1V reference voltage source. The sensor voltage (Vs ) and a 1V reference source (Vref) are the two input signal of your circuit. Your designed circuit should produce an output voltage (V.) to indicate the temperature according to the equation Vo = T/10. (°C/10) i.e and When T=0 °C, Vo = OV T = 100 °C, Vo = 10V. b) Option 2:- Given that a precision analogue temperature sensor produces an output voltage (Vs: n
Transcribed Image Text:Official (Closed) - Non Sensitive (a) Option 1:- Given that the precision temperature sensor produces an output voltage (Vs: sensor output voltage) according to the equation Vs= (11.69mV) T °C +1.8663 V. This equation can be expressed in terms of temperature (T) versus sensor voltage (Vs). ie. T = (Vs-1.8663) / (0.01169) You are to design the amplifier circuit for this sensor using any combination of inverting amplifiers, non-inverting amplifiers, summing amplifiers (No need to use all types of amplifier) together with a 1V reference voltage source. The sensor voltage (Vs ) and a 1V reference source (Vref) are the two input signal of your circuit. Your designed circuit should produce an output voltage (V.) to indicate the temperature according to the equation Vo = T/10. (°C/10) i.e and When T=0 °C, Vo = OV T = 100 °C, Vo = 10V. b) Option 2:- Given that a precision analogue temperature sensor produces an output voltage (Vs: n
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