5.164 20-4f 11₁₂=14001 pm a) If= 1.2.4 C 193 R₁=15-2 P=5KIJ-Pack
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Hello my friend, just rewrite the question on the computer in digital form, not handwriting + also drawing the electrical circuit
Transcribed Image Text:15.164--2p=44
Rs.82
11₁ = 14001 prs
(a) If= 1.24
from figure (2)
by intersect the value
of If=1₁2 to find
the Eart
1² Fo=300TT at Mompre
R₁=15-2 P₁²=5KWU=Punk
Ifel-by
15
JA-18-257A
CONFO
Port = I² R₂
II-
12- 5000-333-333
تكابها
AIf = If I f
ATF= 12-1·03-0·17 A
155
VA-EA-JARA V₁
Since VA TAR₁ = 18-257+15=273-5557²
273-855-E₁ 18 257×0.8 1.5
at 1400 rpm
SE-EEA
tond
-360-25796=10₂04³5
from fignre (2) by intersect the value of
EA= 289 961² with Curre to
Curve to find I'fa
T'p - 103A
W/
Transcribed Image Text:b) а2=1000крас
Чассаттарань
IN-15A
-220=EA+ 1500-8 +1.5
EA₂ 206-5 V at 1000rpm
+7
220V I
C²T = EA TA
271 Tot 206 5% 15
=BA
Shurit
EAT - (1₁/1_) EAT (14.00/1000/206-5=289-1 V at 14ocipe
from figure (2) by Intersect the Vstus of EA
with Curve to find Ife
20 J j = 1.025A
DE 005 EA
AF÷Eo-EA
effective
Es = 289+1+0+5*289-1=303-555 V
by intersect this liatue of to with
Curve in figure (2) to find the actual valuy
of current field.
• If= 1.245 A actual
I = If+ ŢA = 1245+15=16-245A
Tot = 206-5+15 = 29.579///.m
271icco
wront
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