A motor winds the rope in B with a constant acceleration as. Because of the pulley system, the mass m in A slides in this way to the left over a horizontal axis. Between m and the left end point of the horizontal axis, there is a spring (constant k, unstretched length ). The coefficient of kinetic friction between m and the axis is μK. When SA equals 1.5 m, vв equals 6 m/s. For this situation, determine at that instant the velocity of A and the acceleration of A. Data: aв = 2 m/s², m = 2 kg, k = 150 N/m, lo = 2 m, μK = 0.3 2 m B Combination of these equations leads to the solution: VA is 15 m/s to the left, and a = 101 m/s² to the left.

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A motor winds the rope in B with a constant acceleration as. Because of the pulley
system, the mass m in A slides in this way to the left over a horizontal axis.
Between m and the left end point of the horizontal axis, there is a spring (constant
k, unstretched length ). The coefficient of kinetic friction between m and the axis
is μK. When SA equals 1.5 m, vв equals 6 m/s. For this situation, determine at that
instant the velocity of A and the acceleration of A.
Data: aв = 2 m/s², m = 2 kg, k = 150 N/m, l = 2 m, μK = 0.3
2 m
A
B
Combination of these equations leads to the solution: VA is 15 m/s to the left, and aA = 101 m/s² to the
left.
Transcribed Image Text:A motor winds the rope in B with a constant acceleration as. Because of the pulley system, the mass m in A slides in this way to the left over a horizontal axis. Between m and the left end point of the horizontal axis, there is a spring (constant k, unstretched length ). The coefficient of kinetic friction between m and the axis is μK. When SA equals 1.5 m, vв equals 6 m/s. For this situation, determine at that instant the velocity of A and the acceleration of A. Data: aв = 2 m/s², m = 2 kg, k = 150 N/m, l = 2 m, μK = 0.3 2 m A B Combination of these equations leads to the solution: VA is 15 m/s to the left, and aA = 101 m/s² to the left.
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