A mild steel specimen of circular cross- section of length 34.53 mm is subjected to a maximum tensile force of 42.05 KN. An ultimate stress of 17.24 kN/mm2 was generated. The specimen has % of elongation and % of reduction in area 45.22% and 58.94% respectively. Calculate: (1) Diameter of the specimen, (ii) Final diameter (iii) Final length of the specimen, (iv) Find the yielding force and elongation if the stress at yielding is 39.9 N/mm² the yielding force and elongation if the stress at yielding is 39.9 N/mm² and strain is 2.86, and (v) Find Modulus of Elasticity if elongation under an elastic load of 8.31 N is 0.216 mm. Modulus of Elasticity, if elongation under an elastic load of 8.31 N is 0.216 mm. Determine: i) Diameter of the specimen (mm)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A mild steel specimen of circular cross-
section of length 34.53 mm is subjected
to a maximum tensile force of 42.05 KN.
An ultimate stress of 17.24 kN/mm² was
generated. The specimen has % of
elongation and % of reduction in area
45.22 % and 58.94 % respectively.
Calculate:
(i) Diameter of the specimen, (ii) Final
diameter (iii) Final length of the specimen, (iv)
Find the yielding force and elongation if the
stress at yielding is 39.9 N/mm² the yielding
force and elongation if the stress at yielding is
39.9 N/mm² and strain is 2.86, and (v) Find
Modulus of Elasticity if elongation under an
elastic load of 8.31 N is 0.216 mm. Modulus of
Elasticity, if elongation under an elastic load of
8.31 N is 0.216 mm.
Determine:
i) Diameter of the specimen (mm)
ii) Final Diameter (mm)
iii) Final Length of the Specimen (mm)
iv) Yield Force (N), if the stress at yielding is 39.9
N/mm²
v) Elongation (mm), if the strain is 2.86
vi) Modulus of Elasticity (N/mm²)
Transcribed Image Text:A mild steel specimen of circular cross- section of length 34.53 mm is subjected to a maximum tensile force of 42.05 KN. An ultimate stress of 17.24 kN/mm² was generated. The specimen has % of elongation and % of reduction in area 45.22 % and 58.94 % respectively. Calculate: (i) Diameter of the specimen, (ii) Final diameter (iii) Final length of the specimen, (iv) Find the yielding force and elongation if the stress at yielding is 39.9 N/mm² the yielding force and elongation if the stress at yielding is 39.9 N/mm² and strain is 2.86, and (v) Find Modulus of Elasticity if elongation under an elastic load of 8.31 N is 0.216 mm. Modulus of Elasticity, if elongation under an elastic load of 8.31 N is 0.216 mm. Determine: i) Diameter of the specimen (mm) ii) Final Diameter (mm) iii) Final Length of the Specimen (mm) iv) Yield Force (N), if the stress at yielding is 39.9 N/mm² v) Elongation (mm), if the strain is 2.86 vi) Modulus of Elasticity (N/mm²)
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