i need the answer quickly Q 1J-specimen with the dimensions shown in figure no. 1 below) The following table is the values of true stress - true strain of killed steel0.001 0.010 0.049True Stress (psi) 27024 30839 441000.095 0.14051260 55890True Strain0.1820.2230.336593206208341067-D- 3.3".0.03G = 2.0Figure no. 1 the dimension of killed steel specimenPlot the engineering stress strain graph, pointing each point on the graph, and the determineI Modulus of elasticity2- Yield strength3- Tensile strength4 Fracture stress5- Modulus of resilience

Answered: Image /qna-images/answer/8b662570-42ee-4092-bdf9-45f8a2c96b29.jpg

)The following table is the values of true stress-true strain of killed steel specimen with the dimensions shown in figure no. 1 below True Strain True Stress (psi) 27024 30839 44100 0.001 0.010 0.049 0.095 0.140 0.182 0.223 0.336 51260 55890 59320 62083 41067 D-3.3". 0.03 G=20 Figure no. 1 the dimension of killed steel specimen Plot the engineering stress strain graph, pointing each point on the graph, and the determine I Modulus of elasticity 2- Yield strength 3- Tensile strength 4 Fracture stress 5 Modulus of resilience

)The following table is the values of true stress-true strain of killed steel specimen with the dimensions shown in figure no. 1 below True Strain True Stress (psi) 27024 30839 44100 0.001 0.010 0.049 0.095 0.140 0.182 0.223 0.336 51260 55890 59320 62083 41067 D-3.3". 0.03 G=20 Figure no. 1 the dimension of killed steel specimen Plot the engineering stress strain graph, pointing each point on the graph, and the determine I Modulus of elasticity 2- Yield strength 3- Tensile strength 4 Fracture stress 5 Modulus of resilience

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: I need the answer to problem number 7.

A: The industry print shows the 3D view or perspective of a part (angle). The small circle which is…

Q: Prove please!

Q: If a car weighing 2400 lbs is able to go 1000 ft up a mountain incline whose angle of inclination is…

A: Given data: Weight of car = 2400 lbs Distance which car moves up the incline =…

Q: Hi, please complete the last three subparts of this question.

A: To calculate the rate of heat transfer, to derive and to calculate the mass flow rate of water, flow…

Q: Define the Temperature Scales?

Q: ptotic relationship?

A: Power:- Power is the amount of work done in a given amount of time or the rate at which work is…

Q: Thank you, I understand it now! What value of g did you use?

Q: How forces are transmitted?

Q: So no answer and this used one of my questions?

Q: Distinguish between the Surface Loads and the Distributed Loads?

A: Load is defined as an external force or a couple to which a member is subjected during its…

Q: Hello, sorry for not clarifying which parts to solve, could you please do part D?

A: Given data:- The speed of the impact is doubled To find:-the maximum compression of the spring

Q: Texts: A haulage gear is driven by a motor which develops 15 kW at a full speed of 750 rev/min. The…

A: Step 1: Step 2: Step 3: Step 4:

Q: Giant Swing. The "Giant Swing" at a county fair consists of a vertical central shaft with several…

Q: Problem 3: A small gearing system in your brand-new 3D printer fails as you were printing, leading…

A: To prove: We must demonstrate that the equipment failed under normal operating circumstances in…

Q: A rigid tank (a closed system with fixed boundaries) with a volume of 0.45677 m³ contains 10 kg of…

A: Volume of tank, V=0.45677 m3Mass of refrigerant, m=10 kgPressure of vapor (refrigerant) P1=600 kPa,…

Q: How did you arrive at the 115?

Q: Derive Equation 13.3.

A: Consider W1 is the apparent weight of the solid with the sinker submerged, and W2 is the apparent…

Q: Situation: The specific heat of an object can be measured by placing it in thermal contact with…

Question

i need the answer quickly

Q 1J-
specimen with the dimensions shown in figure no. 1 below
) The following table is the values of true stress - true strain of killed steel
0.001 0.010 0.049
True Stress (psi) 27024 30839 44100
0.095 0.140
51260 55890
True Strain
0.182
0.223
0.336
59320
62083
41067
-D- 3.3".
0.03
G = 2.0
Figure no. 1 the dimension of killed steel specimen
Plot the engineering stress strain graph, pointing each point on the graph, and the determine
I Modulus of elasticity
2- Yield strength
3- Tensile strength
4 Fracture stress
5- Modulus of resilience

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

the material had a tensile stress of 67.7 ksi then was unloaded. the original length of the specimen was 5.0 inches. show the line on the diagram you would expect the material to follow as the load was released. estimate the length of the specimen after all load was removed.
2) The stress-strain diagram for an alloy specimen having an original diameter of 0.5 in. and a gage length of 2 in. is shown in the figure below. TENSILE STRESS (MPA) 450 400 350 300 250 200 150 100 50 Part A 0 0 STRESS VS. STRAIN 0.002 0.004 STRAIN 0.006 Determine the modulus of resilience. Show units. Part B Determine the modulus of elasticity of the material. Part C Estimate the Yield Strength of the material. 0.008 0.01
The answer is one of the options below please solve carefully and circle the correct option Please write clear .
How can I solve for the %0.2 offset strain and the calculated stress? Original diameter : 6mm Original length : 30mm Fracture diameter : 4.54mm
Using the stress-strain curve in Figure 3, choose the correct answer for the following questions
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. Question 1 ;Determine the elastic energy absorption capacity (in N.mm) of that specimen. Question 2; Determine the plastic energy absorption capacity (in N.mm) of that specimen.
I am asking because it is a hard question
Hello, I hope you are fine. I need to do this homework in Metal Engineering. I hope to get your help because I have an important homework.
I need the answer as soon as possible
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
The answer is one of the options below please solve carefully and circle the correct option Please write clear .
The following data were obtained during a tensile test of an alluminium alloy specimen. Initial diameter = 18mm Original gauge length = 45mm Final gauge length = 53mm Load at elastic limit = 82kN Yield load = 93kN Maximum load = 168kN Determine the Yield stress - answer to be provided in MPa correct to 3 decimal