A metallic system OA is subjected to two forces FAB and FAC. The force in cable AC is 5 KN. Given FAB = 0.912i + 1.713j - 2.286k (KN) 1.6 m A FAB FAC 2 m *--* 1.5 m 0.8 m B The force FAC (KN) as a vector is represented as The projection of FAB along AC in KN is The angle between AB and AC is Activate Windows Go to Settings to activate Windows. 1.5 m 0.8 m B The force FAC (KN) as a vector is represented as The projection of FAB along AC in KN is The angle between AB and AC is −1.078i + 1.01j – 1.346k 1.452i + 0.851j - 1.034k -1.452i + 0.851j - 1.034k | | -2.695i + 2.525j - 3.365k 2.474 1.355 1.355 1.911 2.314 50.4 65.81 71.02 44.12

A metallic system OA is subjected to two forces FAB and FAC. The force in cable AC is 5 KN. Given FAB = 0.912i + 1.713j - 2.286k (KN) 1.6 m A FAB FAC 2 m -- 1.5 m 0.8 m B The force FAC (KN) as a vector is represented as The projection of FAB along AC in KN is The angle between AB and AC is Activate Windows Go to Settings to activate Windows. 1.5 m 0.8 m B The force FAC (KN) as a vector is represented as The projection of FAB along AC in KN is The angle between AB and AC is −1.078i + 1.01j – 1.346k 1.452i + 0.851j - 1.034k -1.452i + 0.851j - 1.034k | | -2.695i + 2.525j - 3.365k 2.474 1.355 1.355 1.911 2.314 50.4 65.81 71.02 44.12

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.63P: Let A and B be two nonparallel vectors that lie in a common plane S. If C=A(AB), which of the...

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