A metal bar is made out of Ti-6A1-4V titanium (stiffness E = 120 GPa) and has a diameter d = 35 mmwith the end at A fixed to the wall. There is a distributed axial load of w = 60 kN/m. Length of the baris L1 = 1200 mm. Calculate the displacement of point A relative to the wall.L1The displacement at A is 8 =mmw [kN/m]Acc 00BY NO SA2021 Cathy Zupke

Step 1: Step 2: Step 3: Step 4:

Answered: A metal bar is made out of Ti-6A1-4V…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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L = 0.3m A = 20 x 6 mm E= 70 GPa allowable stress = 120 MPa 0.6 m 0.4 m 0.2 m Rigid bar D C W 0.5m 40 x 6 mm 50 GPa wable stress = 80 MPa 16 mm dia. bolt with allowable s 6 mm 80 MPa in bearing and 60 MPa The rigid bar A,B,C,D shown in figure is connected to the ground by a hinge at B and to Magnesium bar at A, Aluminum bar at C. the properties of the bars are shown on the figure. all the connections are using 16 mm bolts in single shear. Determine the maximum safe load W that can be applied. Determine the final position of point D.
The pin-connected structure shown in the figure consists of a rigid beam ABCD and two supporting bars. Bar (1) is a bronze alloy [E = 101 GPa] with a cross-sectional area of A₁ = 230 mm². Bar (2) is an aluminum alloy [E = 71 GPa] with a cross-sectional area of A₂ = 740 mm². All bars are unstressed before the load P is applied; however, there is a 4-mm clearance in the pin connection at A. Assume L₁ = 2040 mm, a = 1020 mm, b = 630 mm, c = 460 mm, and L₂ = 1470 mm. If a load of P = 155 kN is applied at B, determine (a) the normal stresses in both bars (1) and (2). (b) the downward deflection of point A on the rigid bar. (1) L₁ a b B Answers: (a) σ₁ = 02= (b) VA= i i i C MPa MPa mm (2) L2
A circular column is made of concrete [Ec = 4.2(103)ksi] while being reinforced with six steel rods [Est = 29 (103 )ksi]. It is acted upon by an axial force of 30 kip as shown in the figure to the right. Each rod has a diameter of 0.85 in. c) Stress in each steel rod, σst = ____________________ ksi d) Stress in the concrete, σc = ____________________ ksi
answer as soon as possible
A load P is supported by a structure consisting of rigid bar ABC, two identical solid aluminum alloy [E = 73 GPa] rods (1), and a solid bronze [E = 105 GPa] rod (2). The aluminum rods (1) each have a diameter of 10 mm and a length of L₁ = 2.7 m. They are symmetrically positioned relative to middle rod (2) and the applied load P. Bronze rod (2) has a diameter of 25 mm and a length of L₂ = 1.7 m. If all bars are unstressed before the load P is applied, determine the normal stresses in the aluminum and bronze rods after a load of P = 70 KN is applied to the rigid bar. L₁ B Answer: 01 = i 0₂ i L2 (2) (1) (1) MPa MPa
A load P is supported by a structure consisting of rigid bar ABC, two identical solid bronze [E = 17200 ksi] rods, and a solid steel [E = 31400 ksi] rod, as shown. The bronze rods (1) each have a diameter of 0.69 in. and they are symmetrically positioned relative to the center rod (2) and the applied load P. Steel rod (2) has a diameter of 0.53 in. Assume L₁=45 in and L₂=67 in. If all bars are unstressed before the load P is applied, determine the normal stresses in bronze rods (1) and steel rod (2) after a load of P = 16 kips is applied. (1) Answers: 01 02 = i i L2 (2) Save for Later B P eTextbook and Media (1) ksi. ksi. L₁ Attempts: 0 of 5 used Submit Answer
A load P is supported by a structure consisting of rigid bar ABC, two identical solid bronze [E = 14100 ksi] rods, and a solid steel [E = 28000 ksi] rod, as shown. The bronze rods (1) each have a diameter of 0.61 in. and they are symmetrically positioned relative to the center rod (2) and the applied load P. Steel rod (2) has a diameter of 0.47 in. Assume L₁-39 in and L2-72 in. If all bars are unstressed before the load P is applied, determine the normal stresses in bronze rods (1) and steel rod (2) after a load of P = 29 kips is applied. O (1) A Answers: 0₁ = i 0₂ = i L2 (2) B P ksi. ksi. L

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