A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H1 = 4 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P = ii) Stress-induced in the top bar = iii) Stress-induced in the bottom bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H1 = 4 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P = ii) Stress-induced in the top bar = iii) Stress-induced in the bottom bar =

Precision Machining Technology (MindTap Course List)

2nd Edition

ISBN:9781285444543

Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Chapter3: Job Planning, Benchwork, And Layout

Section3.1: Understanding Drawings

Problem 9RQ: A dimension listed on an engineering drawing is known as the _______ _______.

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A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.29 mm the values of elastic modulus for steel is 217 MPa. Take H₁ = 4 cm, H₂ = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 7 x 7 cm. Also, determine the stress-induced in each section of the bar.

i) Magnitude Force, P =

ii) Stress-induced in the top bar =

iii) Stress-induced in the bottom bar =

R cm x Rcm
Steel bar
H1 cm
Q cm x Q cm
Šteel bar
H2 cm

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