A man inside a spherical diving bell watches a fish through a window in the bell, as in the figure below. If the diving bell has radius R = 1.84 m and the fish is a distance p = 1.13 m from the window, calculate the image distance and the magnification. Neglect the thickness of the window. (Use 1.333 and 1.000 for the indices of refraction of water and air, respectively.) HINT (a) the image distance (in m) m Window- (b) the magnification
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- To work this problem, use the fact that the image formed by the first surface becomes the object for the second surface. The figure below shows a piece of glass with index of refraction n = 1.50 surrounded by air. The ends are hemispheres with radii R1 = 2.00 cm and R2 = 4.00 cm, and the centers of the hemispherical ends are separated by a distance of d = 8.68 cm. A point object is in air, a distance of p = 1.08 cm from the left end of the glass. (a) Locate the image of the object due to refraction at the two spherical surfaces.A paperweight is made of a solid glass hemisphere of index of refraction 1.58. The radius of the circular cross section is 3.0 cm. The hemisphere is placed on its flat surface, with the center directly over a 2.0 mm long line drawn on a sheet of paper. What length of line is seen by someone looking vertically down on the hemisphere?Olivia is inspecting the concave primary mirror of the Hubble telescope before its launched into space. She stands 73.4 m, in front of the mirror which has a focal length of 39.9 m What is the image distance, v, of Olivia's image? Let's use the mirror formula with proper sign convention. (Do not enter units, round your answer to two decimal places)
- In the figure, a real inverted image I of an object O is formed by a certain lens (not shown); the object-image separation is d = 57.8 cm, measured along the central axis of the lens. The image is just 1/4 the size of the object. (a) What kind of lens must be used to produce this image? (b) How far from the object must the lens be placed? (c) What is the focal length of the lens? Lens here Axis (a) (b) Number i Units (c) Number i UnitsPlease refer to part (a). Here, alpha (the angle at the top of the triangular prism) is 29.7 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?In the figure, a real inverted image I of an object O is formed by a certain lens (not shown); the object-image separation is d, measured along the central axis of the lens. The image is just 1/4 the size of the object. (a) How far from the object must the lens be placed? NOTE: Express your answers in terms of the given variables. Р (b) What is the focal length of the lens? f = O Lens here d Axis 1↓
- There is a lens combinations between two converging lenses that have focal lengths of f1=13 cm (lens 1) and f2=16 cm (lens 2). They are separated by 56 cm along a horizontal line. There is a lit candle (height ho) placed 36 cm in front of the lens 1 (f1=13 cm). Thus, the separation between the candler and the second lens (f2=16 cm) is 92 cm (image attached) Please draw ray diagram and estimate location of final imageA blue whale eyeball may be taken as a sphere that is about 15 cm in diameter. Assuming that it is filled with material with an index of refraction of 1.5, where would the image form for an object (in water) that is very far away? Just consider the initial image formed by refraction through the front surface. Select answer from the options below 15 cm behind the back of the eye 7.5 cm behind the front surface of the eye 15 cm behind the front surface of the eye Approximately 30 cm behind the back of the eye Approximately 50 cm behind the back of the eyeSpherical refracting surfaces. An object O stands on the central axis of a spherical refracting surface. For this situation (see the table below, all distances are in centimeters), nį is the index of refraction where the object is located, n2 is the index of refraction on the other side of the refracting surface. Find (a) the image distance i, and determine whether the image is (b) real or virtual and (c) on the same side of the surface as object O or on the opposite side. (a) (b) (c) n1 n2 p ri R/V Side 1.5 1.3 +70 +56 (a) Number i Units (b) (c) > >
- A very large piece of clear ice has a cave man frozen inside it. When viewed at an anglefrom the top of the ice the cave man appears to be 1.00 ft below the surface of the ice.What is the actual depth (in units of inches) of the cave man from the top of the ice?The index of refraction of the ice is 1.309 Do NOT use i for the angle of incidence or r for the refracted angleThere is a lens combinations between two converging lenses that have focal lengths of f1=13 cm (lens 1) and f2=16 cm (lens 2). They are separated by 56 cm along a horizontal line. There is a lit candle (height ho) placed 36 cm in front of the lens 1 (f1=13 cm). Thus, the separation between the candler and the second lens (f2=16 cm) is 92 cm Please calculate actual postion of final image. Is it real/imaginary?To work this problem, use the fact that the image formed by the first surface becomes the object for the second surface. The figure below shows a piece of glass with index of refraction n = 1.50 surrounded by air. The ends are hemispheres with radii R₁ = 2.00 cm and R₂ = 4.00 cm, and the centers of the hemispherical ends are separated by a distance of d = 8.06 cm. A point object is in air, a distance of p = 1.06 cm from the left end of the glass. R₁ R₂ d (a) Locate the image of the object due to refraction at the two spherical surfaces. 1.222 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. cm to the right of the second surface (b) Is the image real or virtual? O real O virtual