A major oil company has developed a new gasoline additive that is supposed to increase mileage. To test this hypothesis, ten cars are randomly selected. The cars are driven both with and without the additive. The results are displayed in the following table. Can it be concluded, from the data, that the gasoline additive does significantly increase mileage? Let d=(gas mileage with additive)−(gas mileage without additive)d=(gas mileage with additive)−(gas mileage without additive). Use a significance level of α=0.05α=0.05 for the test. Assume that the gas mileages are normally distributed for the population of all cars both with and without the additive. Car 1 2 3 4 5 6 7 8 9 10 Without additive 22.922.9 20.920.9 11.311.3 27.127.1 9.59.5 19.419.4 16.816.8 16.816.8 20.120.1 27.227.2 With additive 25.625.6 23.623.6 13.313.3 28.728.7 1313 2222 1717 18.218.2 2121 29.629.6 Copy Data Step 2 of 5 : Find the value of the standard deviation of the paired differences. Round your answer to two decimal places.
A major oil company has developed a new gasoline additive that is supposed to increase mileage. To test this hypothesis, ten cars are randomly selected. The cars are driven both with and without the additive. The results are displayed in the following table. Can it be concluded, from the data, that the gasoline additive does significantly increase mileage?
Let d=(gas mileage with additive)−(gas mileage without additive)d=(gas mileage with additive)−(gas mileage without additive). Use a significance level of α=0.05α=0.05 for the test. Assume that the gas mileages are
Car | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
---|---|---|---|---|---|---|---|---|---|---|
Without additive | 22.922.9 | 20.920.9 | 11.311.3 | 27.127.1 | 9.59.5 | 19.419.4 | 16.816.8 | 16.816.8 | 20.120.1 | 27.227.2 |
With additive | 25.625.6 | 23.623.6 | 13.313.3 | 28.728.7 | 1313 | 2222 | 1717 | 18.218.2 | 2121 | 29.629.6 |
Copy Data
Find the value of the standard deviation of the paired differences. Round your answer to two decimal places.
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