A magnesium-lead alloy of mass 6.7 kg consists of a solid a phase that has a composition just slightly below the solubility limit at 300°C (570°F). The magnesium-lead phase diagram is shown in Animated Figure 9.20. (a) What mass of lead is in the alloy? i kg (b) If the alloy is heated to 400°C (750°F), how much more lead may be dissolved in the a phase without exceeding the solubility limit of this phase? kg

A magnesium-lead alloy of mass 6.7 kg consists of a solid a phase that has a composition just slightly below the solubility limit at 300°C (570°F). The magnesium-lead phase diagram is shown in Animated Figure 9.20. (a) What mass of lead is in the alloy? i kg (b) If the alloy is heated to 400°C (750°F), how much more lead may be dissolved in the a phase without exceeding the solubility limit of this phase? kg

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Which line on the above phase diagram corresponds to the Solid-Liquid transition? Answer
The lead and tin are partially dissolved in each other in solid state although they completely dissolved in liquid state. They form eutectic from solid solutions alfa (a) and beta (B) at alloying composition 62% tin and 38% lead, the eutectic forming temperature is 184°C. Alfa contained 20% tin dissolved in 80% lead at 184°C while beta consist of lead dissolved in tin at 184°C. If the 100 g of eutectic contained 45.5 g of alfa at 184°C.Knowing that the melting temperatures of lead and tin are 329°C and 232°C respectively, and the solubility of tin and lead in each other's diminished to zero at room temperature. Answer the following a) Plot the phase diagram for lead-tin system label all phases and temperature. b) What is the composition of beta at eutectic temperature. c) For 40 % lead alloy calculate the phase amount and composition at 350°C, 170°C, and Tr
I need the answer as soon as possible
Explain in detail how to apply the Clausius-Clapeyron equation to generate the phase diagram of a pure substance, explain differences between the different types of phase change.
At what temperature does the first liquid phase form at 90% Ni? T(°C) 1600 1500 1400 1300 1200 1100 1000, L (liquid) L+α solidus liquidus 80 100 20 40 60 80 wt% Ni
Consider Al- Cu system below. When Al-40%Cu is heated above 600°C and cooled slowly to a temperature of 545°C . Answer the following. Use the values of composition given in the phase diagram , no estimation .Each has two marks. 700 1200 600 L a + L 6 +L 548 1000 500 (CUAL) a + 6 800 400 600 300 5.65 10 20 30 32.7 40 50 52.5 (AI) Composition (wt % Cu) a. Percentage of the pro-eutectic phase present (% no decimal places) b. Composition of the pro- eutectic phase present (in %Cu one decimal place) c. What is the percentage of larger eutectic component present (% no decimal places) Temperature (°C) Temperature (°F)
1 Al-Li Aerospace Alloys When a small amount of Li is added into Al to create an Al-Li alloy, the two elements typically do not mix homogeneously. Instead, most of the material is nearly-pure Al, while some small regions are Li-rich.¹ (These small regions are called precipitates and they are responsible for giving Al-Li alloys much better properties for aerospace applications relative to pure Al. We'll learn more about the alloying process and about precipitates later in the course.) The Li-rich regions have the chemical formula Al3Li and belong to the cubic crystal system.² In the unit cell, the Li atoms are located at 000, while the Al atoms are located at 110, 101, and 01121. (a) Draw the unit cell of Al3Li. (b) Which of the crystal structures from Callister Chapter 3 does this resemble? Why do we not call it that structure? (c) Given that the lattice parameter is 0.401 nm, what is the density of Al3Li?
For two hypotetical materials which have limitless solubility for both in the “liquid” and “solid” states in each other, the following data are listed. Melting Temperatures of material A and B are Tm,A and Tm,B respectively, Liquidus and Solidus curves are circular arcs. a- Draw the related “Phase Diagram” of Material A and Material B showing the data given and calculated. b- Calculate/Determine the compositions of phases at T2 , explain the procedure. c- Calculate/Determine the “percentages” of “phases” of Alloy,2 at T2 , explain the procedure. Given: -Tm,A, Celcius =300 -Tm,B, Celcius =800 -T1, Celcius =600 -B percentage of Liquid phase at T1 =25 -B percentage of Solid phase at T1 =70 -B percentage of Alloy 2. =50 -T2, Celcius =650 -B percentage of Liquid phase of Alloy 2 at T2 = to be calculated -B percentage of Solid phase of Alloy 2 at T2 = to be calculated
Determine the composition of the phases;
Temperature ("C) Temperature ($1 Consider 1 kg of Copper - Silver alloy (Cu - Ag) containing 75 wt% Ag. The phase diagram of the alloy is shown in the figure below. The alloy is cooled to 778 °C (just below the eutectic temperature). Calculate the mass in kg of the eutectic phase B (phase B that appears during the eutectic reaction) that forms? Composition (at% Ag 20 40 60 100 2200 80 1200 2000 Liquidus 1000 LIquid 1800 Solidus 1600 800 779°C (T 80 91.2 1400 IC. 1200 600 Solvus T000 400 800 200 20 40 80 100 (Cu) Composioon wt A
In a binary Fe-Fe3C system, what is the transformation that occurs when cooling an austenistic mixture of 2% C by weight from 1100°C to below the eutectoid temperature? What is the microstructure, and how is it formed? What are the concentrations of the total and partial phases? Data: eutectoid temperature: 723 ºC, eutectoid concentration: 0.76% C, limit concentration of ferrite: 0.022%, limit concentration of cementite: 6.7%.
The mass fraction of eutectoid cementite in a hypoeutectoid iron-carbon alloy (just below its eutectoid temperature) is 0.100. On the basis of this information, determine the composition of the alloy. If it is not possible to determine the composition from the information provided, enter 0. 0.7365 wt% C