A living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22011) contains 30.0 mg of carbon. When the sample is placed inside a shielded beta counter with 86% counting efficiency, 833 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample in the nearest year (1 yr ~ 3.156 × 10 s).

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Chapter1: Units, Trigonometry. And Vectors
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A living specimen in equilibrium with the atmosphere contains one atom of 14C
(half-life = 5 730 yr) for
every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose,
C12H22011) contains 30.0
mg of carbon. When the sample is placed inside a shielded beta counter with 86%
counting efficiency,
833 counts are accumulated in one week. Assuming that the cosmic-ray flux and the
Earth's atmosphere
have not changed appreciably since the sample was formed, find the age of the
sample in the nearest year (1 yr ~ 3.156 × 10' s).
Transcribed Image Text:A living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 x 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22011) contains 30.0 mg of carbon. When the sample is placed inside a shielded beta counter with 86% counting efficiency, 833 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample in the nearest year (1 yr ~ 3.156 × 10' s).
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