A living specimen in equilibrium with the atmosphere contains one atom of ¹4℃ (half-life = 5 730 yr) for every 7.7 x 10¹1¹ stable carbon atoms. An archeological sample of wood (cellulose, C12H22O1₁1) contains 21.0 mg of carbon. When the sample is placed inside a shielded beta counter, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample. (Atomic mass of C is 12u)
A living specimen in equilibrium with the atmosphere contains one atom of ¹4℃ (half-life = 5 730 yr) for every 7.7 x 10¹1¹ stable carbon atoms. An archeological sample of wood (cellulose, C12H22O1₁1) contains 21.0 mg of carbon. When the sample is placed inside a shielded beta counter, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth's atmosphere have not changed appreciably since the sample was formed, find the age of the sample. (Atomic mass of C is 12u)
Related questions
Question
A living specimen in equilibrium with the atmosphere contains one atom of 14C (half-life = 5 730 yr) for every 7.7 × 1011 stable carbon atoms. An archeological sample of wood (cellulose, C12H22O11) contains 21.0 mg of carbon. When the sample is placed inside a shielded beta counter, 837 counts are accumulated in one week. Assuming that the cosmic-ray flux and the Earth’s atmosphere have not changed appreciably since the sample was formed, find the age of the sample. ( Atomic mass of C is 12u)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 6 images