A lift of mass 'm' is connected to a rope which is moving upward with maximum acceleration 'a'. For maximum safe stress, the elastic limit of the rope is 'T'. The minimum diameter of the rope is (g = gravitational acceleration)
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A: The strain in the wire is strain=LΔL=2.43×10−4Explanation:Step 1: Given- The mass of the stone is…
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A: See below
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Q: 0.02 1 1.4 0.5 0.04 2 2.8 1 0.06 3 4.2 1.5 0.08 4 5.6 2 0.1 5 7 2.5
A: Solution:
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A: We have the Young's modulus Y=stressstrain
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A: Given : scale of the stress axis is set as s=320 in a unit of 106N/m2 ε=0.0090
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A: The stress experienced when force is applied perpendicular to surface is called compressive stress .
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A: Length of cable L = 2.0 m Cross-sectional area A = 0.07 m2 Mass of machine M = 200 kg Young modulus…
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Q: The table shown in the image below shoes the stress and strain values (in MPa) for a silk spider…
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