Answered: Two cylindrical rods, one steel and the… | bartleby

Related questions

Question

Two cylindrical rods, one steel and the other copper, are
joined end to end. Each rod is 0.750 m long and 1.50 cm in diameter.
The combination is subjected to a tensile force with magnitude 4000 N.
For each rod, what are (a) the strain and (b) the elongation?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A solid copper cube has an edge length of 89.9 cm. How much stress must be applied to the cube to reduce the edge length to 89 cm? The bulk modulus of copper is 1.4 x 101¹ N/m². Number i 4.2 Units N/m^2 or Pa
As illustrated in the figure, consider a circular cylindrical rod tested in a uniaxial tension test. Two points A and B located at a distance lo = 32 cm from each other are marked on the rod, and a tensile force of F = 980 N is applied on the rod. If the tensile strain and tensile stress generated in the rod were ε = 0.06 cm/cm and σ = MPa, determine: (a) The radius, r, of the rod after the application of the force 2.2 (b) The total elongation of the rod, Al, after the application of the force A B F ©
A solid copper cube has an edge length of 89.1 cm. How much stress must be applied to the cube to reduce the edge length to 89 cm? The bulk modulus of copper is 1.4 x 10¹¹ N/m². Number i Units
A man with a mass of 68.3 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm2 and an uncompressed length 50.4 cm. Young’s modulus for compression of the human femur is 9.40 × 109 N/m2. What is the fractional length change of the femur when the person moves from standing on two feet to standing on one foot?
A 1.0 x 10-3 kg spider is hanging vertically by a thread that has a Young’s modulus of 4.5 x 109 N/m 2. What is the cross-sectional area of the thread when strained (strain = 0.1) by the full weight of the spider?
One end of a vertical metallic wire of length 2.8 m and diameter 2.0 mm is attached to a ceiling, and the other end is attached to a 5.0 N weight pan, as shown below. REFER TO PICTURES FOR THE QUESTION. I AM HAVING TROUBLE WITH THE ONE PART.
A sign (mass 2300 kg) hangs from the end of a vertical steel girder with a cross-sectional area of 0.010 m2. Ignore the mass of the girder itself. The elastic modulus for steel is 2.0×10^11N/m2. The stress is 2.3 x 10^6. What is the strain on the girder? It is not 1.2 x 10^-5. I know its stress is divided by the modulus. Not sure what I'm doing wrong. If the girder is 9.90 m long, how much is it lengthened?
A 1.25 m long cable has a diameter 3.50 mm with a Young’s Modulus, E, of 9.75 x 109 N/m2 . When the wire is placed under tension, it experiences a stress of 202.52 x 106 N/m2 , the length of the cable extends by 36.35 mm. Calculate the force that the cable experiences under tension and the strain energy density (U/V) due to deformation. Give your answers in newtons (N) to 2 decimal places for the force; and in joules per cubic metre (J/m3 ) for the strain energy density to 2 decimal places. Assume the cable is solid and the material is homogeneous.