A life satisfaction test gives high scores for high life satisfaction and low scores for low life satisfaction. A research study was conducted to examine whether the life satisfaction level in the United States is greater than the worldwide average. The worldwide average is known to be 30. Let X denotes the sample average. In the study, 40 randomly selected US citizens were given the life satisfaction test. The sample mean is = 34 and the sample variance is s² = 12. Assuming that the satisfaction level is normally distributed, find the critical region of the test and make a decision whether to reject Ho at the significance level 0.05. One of these may be helpful: qt (0.05, 39, lower.tail=FALSE) = 1.684875 qt (0.025, 39, lower.tail=FALSE) = 2.022691 qt (0.05, 40, lower.tail=FALSE) = 1.683851 qt (0.025, 40, lower.tail=FALSE) = 2.021075 Which of the following answers is correct in all of its parts? -30 O The critical region is the interval (1.684875, oo) and since the value of the test statistic ist= =7.302967, we reject Hoμ = 30 and conclude Haμ> 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. O The critical region is the set C= {te R||t| > 2.021075} the value of the test statistic is t = = (-0, 2.021075) U (2.021075, co) and since -30 =7.302967, we reject Ho: μ = 30 and conclude Haμ> 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. -30 The critical region is the interval (1.683851, ∞) and since the value of the test statistic ist= =7.302967, we reject Hoμ= 30 and conclude Ha > 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. -30 The critical region is the interval (2.022691, ∞) and since the value of the test statistic ist = =7.302967, we reject Hoμ = 30 and conclude Ha > 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average.
A life satisfaction test gives high scores for high life satisfaction and low scores for low life satisfaction. A research study was conducted to examine whether the life satisfaction level in the United States is greater than the worldwide average. The worldwide average is known to be 30. Let X denotes the sample average. In the study, 40 randomly selected US citizens were given the life satisfaction test. The sample mean is = 34 and the sample variance is s² = 12. Assuming that the satisfaction level is normally distributed, find the critical region of the test and make a decision whether to reject Ho at the significance level 0.05. One of these may be helpful: qt (0.05, 39, lower.tail=FALSE) = 1.684875 qt (0.025, 39, lower.tail=FALSE) = 2.022691 qt (0.05, 40, lower.tail=FALSE) = 1.683851 qt (0.025, 40, lower.tail=FALSE) = 2.021075 Which of the following answers is correct in all of its parts? -30 O The critical region is the interval (1.684875, oo) and since the value of the test statistic ist= =7.302967, we reject Hoμ = 30 and conclude Haμ> 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. O The critical region is the set C= {te R||t| > 2.021075} the value of the test statistic is t = = (-0, 2.021075) U (2.021075, co) and since -30 =7.302967, we reject Ho: μ = 30 and conclude Haμ> 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. -30 The critical region is the interval (1.683851, ∞) and since the value of the test statistic ist= =7.302967, we reject Hoμ= 30 and conclude Ha > 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average. -30 The critical region is the interval (2.022691, ∞) and since the value of the test statistic ist = =7.302967, we reject Hoμ = 30 and conclude Ha > 30, i.e. that US citizens score higher on the life satisfaction test than the worldwide average.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Transcribed Image Text:A life satisfaction test gives high scores for high life satisfaction and low scores
for low life satisfaction. A research study was conducted to examine whether the
life satisfaction level in the United States is greater than the worldwide average.
The worldwide average is known to be 30. Let X denotes the sample average. In
the study, 40 randomly selected US citizens were given the life satisfaction test.
The sample mean is = 34 and the sample variance is s² = 12. Assuming that the
satisfaction level is normally distributed, find the critical region of the test and
make a decision whether to reject Ho at the significance level 0.05.
One of these may be helpful:
qt (0.05, 39, lower.tail=FALSE) = 1.684875
qt (0.025, 39, lower.tail=FALSE) = 2.022691
qt (0.05, 40, lower.tail=FALSE) = 1.683851
qt (0.025, 40, lower.tail=FALSE) = 2.021075
Which of the following answers is correct in all of its parts?
Transcribed Image Text:-30
O The critical region is the interval (1.684875, oo) and since the value of the test statistic
ist=
=7.302967, we reject Hoμ = 30 and conclude Haμ> 30, i.e. that US
citizens score higher on the life satisfaction test than the worldwide average.
O The critical region is the set
C= {te R||t| > 2.021075}
the value of the test statistic is t =
=
(-0, 2.021075) U (2.021075, co) and since
-30
=7.302967, we reject Ho: μ = 30 and
conclude Haμ> 30, i.e. that US citizens score higher on the life satisfaction test than
the worldwide average.
-30
The critical region is the interval (1.683851, ∞) and since the value of the test statistic
ist= =7.302967, we reject Hoμ= 30 and conclude Ha > 30, i.e. that US
citizens score higher on the life satisfaction test than the worldwide average.
-30
The critical region is the interval (2.022691, ∞) and since the value of the test statistic
ist = =7.302967, we reject Hoμ = 30 and conclude Ha > 30, i.e. that US
citizens score higher on the life satisfaction test than the worldwide average.
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