A lens is made of glass that has refractive index 1.60. In air, the lens has focal length +18.0 cm. What is the focal length of this lens if it is totally immersed in a liquid that has refractive index 1.42?
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A lens
is made of glass that has refractive index 1.60. In air, the lens has focal
length +18.0 cm. What is the focal length of this lens if it is totally immersed
in a liquid that has refractive index 1.42?
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Solved in 4 steps
- A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used in combination. The converging lens has a focal length of 15.3 cm. The diverging lens is of unknown focal length. An object is placed 19.5 cm in front of the converging lens; the final image is virtual and is formed 12.0 cm in front of the diverging lens. What is the focal length of the diverging lens?A converging lens causes an object 58 cm from the lens to create an image 74.5 cm from the lens on the opposite side of the lens. What is the focal length (in cm) of this lens?On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cm
- A lens grinder wants to make a plane-convex lens with the radius of curvature 0.44 m and the focal length 0.8 m. What refractive index should the glass have?Mike holds a magnifying glass (convex lens) 5.00 cm above a sheet of paper. He looks at the writing on the page and notices that it is magnified by a factor of 3.00. What is the focal length of the lens he is using? a 2.00 cm b 4.00 cm c 7.50 cm d 3.75 cmAn object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright inverted
- A man standing 1.54 m in front of a shaving mirror produces an inverted image 18.6 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size? cm A contact lens is made of plastic with an index of refraction of 1.40. The lens has an outer radius of curvature of +1.92 cm and an inner radius of curvature of +2.47 cm. What is the focal length of the lens? cmYou are tasked with sourcing a lens which will be made out of glass with refractive index 1.668, and is submersed in a liquid with refractive index 1.379. You want a focal length of 6.5 cm, and the radius of curvature of the first side of the lens is 7.4 cm. What radius of curvature is required for the second side, in cm? [Note the first/second lens surface radius is conventionally positive/negative for convex.]The object is located at a distance of 20 cm from the lens, which forms upright image double of the size of the object. What is the focal distance of the lens? O- 5 cm O +0.4 m 10 cm O +20 cm O-0.2 m O-40 cm
- The focal points of a diverging lens are 25.0 cm from the lens. An object is placed 15.0 cm in front of the lens. What is the magnification of the image produced?A convex lens has a focal length of 16 cm. A candle with a height of 6 cm is 15 cm away from the lens. Find the location of the image. If the image is real give a positive answer and a virtual image should be a negative answer.