A lac operon containing one mutation was cloned into a plasmid, which wasintroduced by transformation into a bacterium containing a wild-type lacoperon. The three genes of the chromosomal operon were rendered nonin-ducible in the presence of the plasmid.(a) What kind of mutation in the plasmid operon could have this effect?(b) Suppose the result of transformation was to cause the three plasmid lacgenes to be expressed constitutively, at a high level. What type of plasmidgene mutation could have this result?

(a) The plasma i gene forms such a type of repressor that will not be able to bind the inducer.

Answered: A lac operon containing one mutation…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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If a researcher moves the promoter for the lac operon to the region between the beta galactosidase (lacZ) gene and the permease (lacY) gene, which of the following results would you expect? A) The three genes of the lac operon will be expressed normally. B) The repressor will not be able to bind to the operon. C) The operon will still transcribe the lacZ and lacY genes, but the mRNA will not be translated. D) LacZ will not be transcribed and Beta galactosidase will not be produced.
Strain ROFL4 has a premature stop mutation in the lacZ gene, resulting in a nonfunctional b-galactosidase. Otherwise all other parts of the operon are functional. 1. Can strain ROFL4 metabolize lactose if it is present? 2. If lactose is absent, will strain ROFL4 transcribe its lac operon? 3. If lactose is present, will strain ROFL4 transcribe its lac operon?
11
Strain ROFL4 has a premature stop mutation in the lacZ gene, resulting in a nonfunctional b-galactosidase. Otherwise all other parts of the operon are functional. Circle the least number of components for an F' plasmid that will restore normal regulation and function of the lac operon in the resulting partial diploid. (may need more than one) (a) lacI+ (b) lacO+ (c) lacP+ (d) lacZ+ (e) None, cannot be restored.
You have E. coli growing in HIGH lactose and HIGH glucose. You measure the amounts of protein and find that all three lac operon proteins are present. What rare mutation will give you this result? There are several possibilities (Hint: the biosynthesis of repressor and CAP proteins is constitutive. What kind of mutation would make the activity constitutive?)
The organization and function of the lac operon in E. coli is shown in the following figures: XXI Transcription Repressor mRNA Translation RNA polymerase M M Flask ZYA XXXX Active M-repressor protein Repressor active, operon off. The repressor protein binds with the operator, preventing transcription from the operon. (a) An inducible operon Copyright © 2007 Pearson Education, Inc., publishing as Benjamin Cummings Allolactose (inducer) Carbon/Energy Source 0 Z MInactive repressor protein (a) An inducible operon Transcription Translation XXX Permease B-Galactosidase Transacetylase Operon mRNA 3 Repressor inactive, operon on. When the inducer allolactose binds to the repressor protein, the inactivated repressor can no longer block transcription. The structural genes are transcribed, ultimately resulting in the production of the enzymes needed for lactose catabolism. Copyright © 2007 Pearson Education, Inc., publishing as Benjamin Cummings Suppose you inoculate three flasks of minimal…
A newly identified protein from the cells of the Panopyra plant on Pandora was shown to inhibit translation of its target genes by binding to the 5’ UTR of the mRNA and preventing ribosome binding. A possible way this inhibition may be relieved by an sRNA would be: Group of answer choices a)The sRNA acts as a silencer, suppressing the inhibitory protein and allowing translation to take place. b)The sRNA acts as a decoy, sequestering the inhibitory protein and allowing translation to take place. c)The sRNA acts as a marker, flagging the inhibitory protein for ubiquitination and allowing translation to take place.
A sample of E.coli cells is transformed with a plasmid containing a transcriptional fusion including the promoter of an E.coli housekeeping gene and the LacZ gene. The transformed cells are plated out on selective medium containing X-gal. Which of the following best describes the likely results. a. Colonies will only be blue if lactose is also included in the growth medium. b. Colonies will only be blue if lactose and glucose are included in the growth medium c. Most of the colonies should turn blue. d. Presence of any white colonies may indicate deletion or mutation of the promoter. e. Both c. and d. are correct

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