A laboratory in New Mexico is interested in finding the mean chloride level for a healthy resident in the state. A random sample of 100 healthy residents has a mEq mEq . If it is known that the chloride levels in healthy individuals residing in New Mexico have a standard deviation of 37 L mean chloride level of 99 find a 99% confidence interval for the true mean chloride level of all healthy New Mexico residents. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit:| Upper limit: |
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- Mason earned a score of 226 on Exam A that had a mean of 250 and a standard deviation of 40. He is about to take Exam B that has a mean of 550 and a standard deviation of 25. How well must Mason score on Exam B in order to do equivalently well as he did on Exam A? Assume that scores on each exam are normally distributed.Unfortunately, arsenic occurs naturally in some ground water.† A mean arsenic level of μ = 8.3 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 41 tests gave a sample mean of x = 7.3 ppb arsenic, with s = 2.4 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8.3 ppb? Use ? = 0.01. (a) What is the level of significance? State the null hypotheses H0 and the alternate hypothesis H1 . H0 : μ ---Select--- < ≥ ≤ = > ≠ H1 : μ ---Select--- < > ≤ ≥ = ≠ (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The standard normal, since the sample size is large and σ is known.The Student's t, since the sample size is large and σ is known. The standard normal, since the sample size is large and σ is unknown. The Student's t, since the…In the general population, IQ scores are normally distributed with a mean of 95 and a standard deviation of 17. You wish to examine whether post-graduates at RMIT have a different level of intelligence than the general population. You sampled 29 RMIT postgraduates and measured their IQ which resulted in a mean of 116 and a standard deviation of 14.4. Calculate Cohen's d. Give your answer to 2 decimal places.
- Does it take a different amount of time for seeds to germinate if they are near rock music that is continuously playing compared to being near classical music? The 48 seeds that were exposed to rock music took an average of 28 days to germinate. The standard deviation was 13 days. The 47 seeds that were exposed to classical music took an average of 32 days to germinate. The standard deviation for these seeds was 10 days. What can be concluded at the a - 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer Select an answers Select an answerv (please enter a decimal) Hị: Select an answer Select an answer Select an answer v (Please enter a decimal) c. The test statistic ?- (please show your answer to 3 decimal places.) d. The p-value- (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select g. Thus, the final conclusion is that . answer v the null…It takes an average of 9.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 52 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 1.98 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean, z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer = ≠ < > H1:H1: ? p μ Select an answer < ≠ > = The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept…It takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 65 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.05 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 14.5 at αα = 0.05, so there is statistically significant…
- It takes an average of 10.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 46 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.98 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean =Correct __?__ H1:H1: mean > Correct_ __?__ The test statistic t = __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)An old medical textbook states that the mean sodium level for healthy adults is 140 mEq per liter of blood. A medical researcher believes that, because of modern dietary habits, the mean sodium level for healthy adults, u, now differs from that given in the textbook. A random sample of 23 healthy adults is evaluated. The mean sodium level for the sample is 147 mEq per liter of blood. It is known that the population standard deviation of adult sodium levels is 14 mEq. Assume that the population is normally distributed. Can we conclude, at the 0.10 level of significance, that the population mean adult sodium level differs from that given in the textbook? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂:0 H₁ :0 (b) Determine the type of test statistic to…A random sample of 34 chemists from Washington state shows an average salary of $41857, the population standard deviation for chemist salaries in Washington state is $697. A random sample of 35 chemists from Florida state shows an average salary of $44632, the population standard deviation for chemist salaries in Florida state is $900. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.05 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: Ο Ηο: μι μ2(claim) Ο Ηο: μι 2 με HAM12(claim) Ho: M₁ = H2 1 HAM12(claim) Since the level of significance is 0.05 the critical value is 1.96 and -1.96 The test statistic is: (round to 3 places) The p-value is: (round to 3 places)
- The Weather Underground reported that the mean amount of summer rainfall for the northeastern US is at least 11.52 inches. Ten cities in the northeast are randomly selected and the mean rainfall amount is calculated to be 7.42 inches with a standard deviation of 1.3 inches. At the α = 0.05 level, can it be concluded that the mean rainfall was below the reported average? What if α = 0.01? Assume the amount of summer rainfall follows a normal distribution. Please also state if the assumption of normal distribution was essential for solving this question. You will need to specify the appropriate hypothesis, identify the statistical test, estimate p-value (using R command), and state your conclusion in the context of the problem. For the conclusion, please use the following template. If you reject the null writeSince p-value is [write the value of your p-value] and is less than [write the value of alpha inpercent] we reject the null hypothesis at [write the value of alpha]% significance…The manufacturer of a particular brand of tires claims they average at least 50,000 miles before needing to be replaced. From past studies of this tire, it is known that the population standard deviation is 8,000 miles. A survey of tire owners was conducted. From the 23 tires surveyed, the mean lifespan was 43500 miles. Using alpha = 0.05, can we prove that the data in inconsistent with the manufacturers claim? We should use a t v test. What are the correct hypotheses? Ho: Select an answer v| ? v H Select an answer | ? v Based on the hypotheses, find the following: Test Statistic= p-value- The correct decision is to Select an answer The correct conclusion would be: Select an answer Question Help: M Message İnstructor Submit Question MacBook Pro FR.I END.S DD F8 F9 F10 F11 F12 F7 & 8 9 deleteIt takes an average of 14 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 43 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.5 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.1 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 14 at αα = 0.01, so there is statistically significant…