A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below. G6P 2 F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate AG° at 298 K. 4.0 1.67 kJ/mol (b) Calculate AG when Q, the [F6P]/[G6P] ratio, equals 21.0. 4.0 9.21 kJ/mol (c) Calculate AG when Q = 0.800. 4.0 1.12 kJ/mol (d) Calculate Q in the cell if AG = -2.90 kJ/mol.

A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below. G6P 2 F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate AG° at 298 K. 4.0 1.67 kJ/mol (b) Calculate AG when Q, the [F6P]/[G6P] ratio, equals 21.0. 4.0 9.21 kJ/mol (c) Calculate AG when Q = 0.800. 4.0 1.12 kJ/mol (d) Calculate Q in the cell if AG = -2.90 kJ/mol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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