a K 6.0 cm 15.0 cm 1 a 10.0 cm 15.0 cm b 5.0 cm 42 Two point charges q1 and q2 of -300 nC and 300 nC, respectively, are separated by a distance of 0.15 m. Calculate the electric field caused by q1, the field caused by q2, and the total field. a) at point a Eq₁ = b) at point c Eq₁ = Eq₂=_ , Eq₂=. _ET=_ _E₁=

a K 6.0 cm 15.0 cm 1 a 10.0 cm 15.0 cm b 5.0 cm 42 Two point charges q1 and q2 of -300 nC and 300 nC, respectively, are separated by a distance of 0.15 m. Calculate the electric field caused by q1, the field caused by q2, and the total field. a) at point a Eq₁ = b) at point c Eq₁ = Eq₂=_ , Eq₂=. _ET=_ _E₁=

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

1. Two point charges q₁ and q2 both have a charge equal to +6.0 nC and are on the y axis at y₁ = +3.0 cm and y2 = -3.0 cm respectively. a. What is the magnitude and direction of the electric field on the x axis at x = 4.0 cm? b. What is the force exerted on a third change qo= 2.0 nC when it is placed on the x axis at x = 4.0 cm?
Q1 - 20.0 nC 8. A certain electric quadrupole is made by arranging three point charges as shown below. Assume the distances Q2 = + 20.0 nC P from Q1 to Q2 and from Q2 to Q3 18.0 cm are equal. 24.0 cm - 20.0 nC A small pith ball of mass 0.40 g and a charge of +5.50 nC is placed at point P and released from rest. Find the magnitude and direction of its acceleration. If the signs in Q1, Q2, and Q3 were reversed, how would the acceleration change, if at all? Explain using physical reasoning.
A positive charge of magnitude Q1 = 0.45 nC is located at the origin. A negative charge Q2 = -6.5 nC is located on the positive x-axis at x = 17 cm from the origin. The point P is located y = 17 cm above charge Q2. a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. c) Calculate the y-component of the electric field at point P due to the Charge Q2. Write your answer in units of N/C.
2. Three charges are placed on the vertices of an equilateral triangle whose side is 0.025 m. Find the net electric field at the center of the base of the triangle (point P). q1= - 3.0 mC +4.0 nC. q2= -2.0 nC , q3= q1 q2 q3
Four point charges of equal magnitude are placed on the corners of a rectangle. Q=55nC, side lengths D1= 25.0 cm and D2= 10cm. The charges on the left side are positive and the charges on the right side are negative. a. calculate the value of the horizontal component of the net force, in newtons, on the charge located on the lower left corner of the rectangle. b. calculate the value of the vertical component of the net force, in newtons c. calculate the magnitude of the net force, in newtons on the charge located at the lower left corner of the rectangle. d. calculate the angle in degrees betweeen -180 and 180 that the net force makes measures from the positive horizontal direction
1. A straight wire AB of length 40 cm is charged 20 µC. Both ends wires A and B are located at coordinates A (-40.0) and B (0.0). Point P is at 30 cm above point B (0.30). Determine: a. Electric field at P due to charged straight wire. b. Electric force experienced by Q = +10-7C when it is located at P. 30 ст 40 сm
Q3) Two point charges (Q = + 5.0 µC and Q2 = – 2.0 µ C) are held in place along the x-axis. Q, is at x1 = - 3.0 cm and Q, is at x2 = + 2.0 cm. a) Determine the electric field at (x, y) = (0,4.0 cm) in SI units. Represent your answer as a vector. Start with drawing a picture and setting up an appropriate coordinate system. b) Determine in what region along the x-axis it's possible for the electric field to be zero. There are three distinct regions: -o < x < x1, X1 < x < x2, and x2 < x < ∞ (this excludes x → ±∞ since the electric field is zero there). c) Now that you know in what region it's possible for the electric field to be zero, write out an expression you could solution to find exactly where this location is. Note: you DON'T have to solve it. d) Another charge (Q3 Newtons? Represent your answer as a vector. Hint: no need to apply Coulomb's law to Q3, you already know the electric field at this point. 4.0 µ C) is now placed at (x, y) = (0,4.0 cm). What is the net force on this…
Three electric charges q₁ = +4.0 nC, q₂ = 93 = +2.0 nC are placed on the three corners of a square of side 4.0 cm as shown in the figure below. Calculate the electric field E at the center O of the square. 92 y 91 93 x
= + 4.0 nc located at the origin of a consider an electric dipole consisting of a point charge q1 coordinate system and a second charge q2 = - 4.0 nc located at (0.10 m, 0 m). 0.15 m 0.05 m 0.05 m q1 q2 a) find the electric field at points (0.05 ,0 m) and (0.05 m, 0.15 m) due to this dipole. b) what is the electric force on a 2.0 nc charge placed at these points. c) use the far-field approximation to find the electric field e at a point 1.5 m away from the dipole along the perpendicular bisector at coordinates (0.05 m, 1.5 m)?
A long, thin wire along the x-axis has a linear charge density of 8.8e-6 C/m. a) Find the magnitude of the electric field at point p a distance of 0.8 m from the wire. b) Find the magnitude of the net force on a test charge of 8e-6 C at point p. c) Which direction will the test charge accelerate? parallel to wire perpendicular to and toward wire perpendicular to and away from wire
Two small beads having positive charges q₁ = 29q and q2 = q are fixed at the opposite ends of a horizontal insulating rod of length d = 1.50 m. The bead with charge q₁ is at the origin. As shown in the figure below, a third small, charged bead is free to slide on the rod. 91 + d 92 (a) At what position x is the third bead in equilibrium? x = 0.87868 -0.879 m (b) Can the equilibrium be stable? OYes, if the third bead has a positive charge O Yes, if the third bead has a negative charge O No
2D Electric Fields OPEN d, 2₁ Two point charges Q₁ = 4.58 nC and Q₂-2.4 nC are shown in the figure. Q: is located at (81.1 cm, 0.0 cm) while Q₂ is at (0.0 cm, -75.6 cm). (A) Find the components (E, and E,) for the electric field at (A) which is at the origin. E, - Ey= (B) Find the magnitude and angle of the electric field vector E Note: Angles are measured from the positive x-axis in the counter-clockwise direction. |E|- 4. 08- degrees. I am finished.