3 point charges are located in a circular arc as shown in the figure. a) Obtain the electric field at point P (center of the circle). b)Find the electric force exerted on a point charge -5.0 nC located at P. 4.0cm 4.0cm 60.0 a 30.0° 3.0nC P ID 3.OnC -2.0nC
Q: Three point charges are arranged as shown in Figure P19.13. 5.00 nC -3.00 nC 0.300 m 0.100 m 9…
A: Given, q = 5.00 nC
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Q: Three point charges are arranged as shown in the figure below. 5.00 nC -3.00 nC 0.300 m 0.100 m :…
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- Find the electric field at the location of qa in the figure given that qb = qc = qd = +2.00 mC, q = -1.00 nC, and the square is 20.0 cm on a side. a) Calculare the electric field at qa due to q and qd (add the fields due to those two charges together). Give a positive value if the field is in the second quadrant, and negative if it is in the fourth quadrant. b) Now calculate the field due to qb and qc. Add the fields together, remembering that they are vectors. GIve a positive value for 2nd quadrant, negative for 4th.6| 17 aölJI - 2 uacl X 10 uluilg (-) X Content Google dai X 9 https://blackboard.uob.edu.bh/ultra/courses/ 24065 1/cl/outline Not syncing Remaining Time: 29 minutes, 53 seconds. * Question Completion Status: Consider a uniformly charged ring of radius R-0.2 m and linear charge density 2-3 µC/m as shown in the figure. Find the electric potential (in V) at (p) a distance 0.7 m from the center. 0 0.7 m 3.1x 10* 6.2 x 104 O9.3x 104 7.8x 104 O 4.7x10 7:05 PN 4/3/202 archQuestion 4. Three equal positive charges are at the corners of an equilateral triangle of side a as in Figure 4. Assume the three charges together create an electric field. a) Sketch the electric field lines in the plane of the charges. b) Find the location of one point (other than infinity) where the electric field is zero. c) What are the magnitude and the direction of the electric field at P due to the two charges at the base? Figure 4:
- A point charge gives rise to an electric field with magnitude 4 N/C at a distance of 9 m. If the distance is increased to 45 m, then what will be the new magnitude of the electric field? N/CA proton is released from rest in a uniform electric field of magnitude 415 N/C. (a) Find the electric force on the proton. magnitude N direction (b) Find the acceleration of the proton. magnitude m/s2 direction (c) Find the distance it travels in 1.80 ?s. cma K 6.0 cm 15.0 cm 1 a 10.0 cm 15.0 cm b 5.0 cm 42 Two point charges q1 and q2 of -300 nC and 300 nC, respectively, are separated by a distance of 0.15 m. Calculate the electric field caused by q1, the field caused by q2, and the total field. a) at point a Eq₁ = b) at point c Eq₁ = Eq₂=_ , Eq₂=. _ET=_ _E₁=
- 1) Sketch the electric field lines on top of the figure above. Also sketch the electric field vector atpoint P. 2) Integrate to find the value of the electric field at point P.3) Find the force that would act on a 2.0 μC charge placed at point P.A long, thin wire along the x-axis has a linear charge density of 8.8e-6 C/m. a) Find the magnitude of the electric field at point p a distance of 0.8 m from the wire. b) Find the magnitude of the net force on a test charge of 8e-6 C at point p. c) Which direction will the test charge accelerate? parallel to wire perpendicular to and toward wire perpendicular to and away from wire