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Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction. +3.00 nC -2.00 nC 30.0° 30.0° +3.00 nC (a) What is the total electric field at P, the center of the arc? E = Î N/C + ĵ N/C (b) Find the electric force that would be exerted on a -5.43-nC point charge placed at P. F = |ÎN +

Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction. +3.00 nC -2.00 nC 30.0° 30.0° +3.00 nC (a) What is the total electric field at P, the center of the arc? E = Î N/C + ĵ N/C (b) Find the electric force that would be exerted on a -5.43-nC point charge placed at P. F = |ÎN +

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Chapter 22

Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction.) +3.00 nC -2.00 nC/ 30.0° 30.0° +3.00 nC (a) What is the total electric field at P, the center of the arc? E = |î N/C + j N/C (b) Find the electric force that would be exerted on a -5.43-nC point charge placed at P. F = ÎN +
Transcribed Image Text:Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction.) +3.00 nC -2.00 nC/ 30.0° 30.0° +3.00 nC (a) What is the total electric field at P, the center of the arc? E = |î N/C + j N/C (b) Find the electric force that would be exerted on a -5.43-nC point charge placed at P. F = ÎN +
Expert Solution
Step 1

Given-

r = 4.40 cm = 4.40  x 10-2 m

q1 = q3 = 3 nC =3 x 10-9 C

q2 = -2 nC = -2 x 10-9 C

θ = 30°

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