1. A configuration of charges is shown below. q = 5 nC E 0 E net -29 5 +q The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. +3q -2a E 10 -9 x (cm) E x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. N ta E. +3q

1. A configuration of charges is shown below. q = 5 nC E 0 E net -29 5 +q The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. +3q -2a E 10 -9 x (cm) E x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. N ta E. +3q

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

1. A configuration of charges is shown below. q = 5 nC
E
0
E
net
-29
5
+q
The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below.
The direction of the electric field due to a point charge at any point is along the line joining the charge
and the point and away from the charge for a positive charge and towards the charge for a negative
charge.
+3q
-2a
E
10
-9
x (cm)
E
x= 11 cm
The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in
the positive x-direction. The strength of the field is determined by the charge and the distance
between the charge and the point.
The net electric field in Part 1 will point in the positive x-direction.
(a) Find the total electric field at x = 11 cm.
N
ta E.
+3q

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