1. A configuration of charges is shown below. q = 5 nC Enet 0 = -29 E 5 +q The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. -2a +3q N с 10 E +39 x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. x (cm) E -9 E -q
1. A configuration of charges is shown below. q = 5 nC Enet 0 = -29 E 5 +q The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. -2a +3q N с 10 E +39 x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. x (cm) E -9 E -q
Related questions
Question
HELP ASAP!!
Transcribed Image Text:1.
configuration of charges is shown below. q = 5 nC
0
E
-29
-2a
5
+q
✓
+3q
The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below.
The direction of the electric field due to a point charge at any point is along the line joining the charge
and the point and away from the charge for a positive charge and towards the charge for a negative
charge.
N
10
E
x (cm)
E
x= 11 cm
The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in
the positive x-direction. The strength of the field is determined by the charge and the distance
between the charge and the point.
The net electric field in Part 1 will point in the positive x-direction.
(a) Find the total electric field at x = 11 cm.
E net
-q
ta E,
+3q
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
