Question 5Which of the following statements about the assumption of sphericity is not true?AIt is the assumption that the variances for levels of a repeated-measures variable are equal.BсDIt is tested using Mauchly's test in SPSS.It is automatically met when a variable has only two levels.It is not assumed by multivariate tests.1:43:22

Answered: Image /qna-images/answer/ea662213-e571-4dd6-9713-4d26e7c46f80.jpg

Answered: A It is the assumption that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Earlier this semester, we learned to use 2-Sample-TTest to compare the population means of two independent populations. One-way ANOVA is more powerful because it could compare the population means of three or more independent populations. However, use of one-way ANOVA also requires the assumption that the populations have the same variance. In this exercise, we will compare and contrast One-way ANOVA and 2-Sample-TTest. With the 2-Sample- TTEST, we will first choose 'No' for the pooled variances option, then re-run the test while choosing 'Yes' for the pooled variances option. Use the following data to complete these tasks. Depending on if you choose to do this by hand or using code, use the data format that suits you best - LONG form on top or WIDE form on bottom. Treatment One One One One One One One One Two Two Two Two Two Two Two Two Treatment Treatment One Two 5.6 4.7 3.6 3.9 5.2 4.3 4.1 4.8 Response 5.6 4.7 3.6 3.9 5.2 4.3 4.1 4.8 3.4 2.3 4.4 3.5 3.7 5.8 2.8 4.7 p-value= 3.4 2.3…
A clinical trial for a psychological therapy for trauma takes 37 women and gives them one treatment for trauma and then, a year later, gives them a different treatment. The measure used to indicate success is a Likert scale where 5 means 'l found the treatment very helpful' and 1 means 'l didn't find it helpful at all. The lead researcher gathers the data and she finds a very high variance of scores across the women in each treatment, and considers giving up the analysis. She plans to do a difference in means analysis with unequal variances (she tested and found the variances were unequal). She asks for your advice: a. She is being too hasty because she is using the wrong technique. This is a paired sample and when she takes the difference in the Likert scale for each subject across the two treatments the variance of the remaining lifferences might be so low that she can detect which treatment is statistically better b. She cannot give different treatments to the same people - it…
Explain what would happen to the F ratio of this analysis of variance if 2 points were added to each score in Finals only group? (Note: The new scores would be 2, 4, 2, and 4 with T = 12 and SS = 4.)
suppose the number of off springs a female eagle raises during its lifetime has a disturibution mean 14 and variance 4.7 in an area, 45 rescued and cured female eagles are set free. if these eagles are assumed to be independent (no lack of male partners and food resources) the total number of off springs produced by these eagles can be assumed to have a normal distirubition with mean ...... and variance .... what will the values of mean and variance ?
Two coworkers commute from the same building. They are interested in whether or not there is any variation in the time it takes them to drive to work. They each record their times for 20 commutes. The first worker's times have a variance of 12.2. The second worker's times have a variance of 16.9. The first worker thinks that he is more consistent with his commute times and that his commute time is shorter. Test the claim at the 10% level.What is the F statistic? (Round your answer to two decimal places.)
You are testing the claim that having lights on at night increases weight gain (abstract). A sample of 10 mice lived in an environment with bright light on all of the time and 8 mice who lived in an environment with a normal light/dark cycle is given below. Test the claim using a 10% level of significance. Assume the population variances are unequal and that the weight changes are normally distributed. Give answers to 3 decimal places. Data available at StatKey, choose Mice Wgt Gain-2e data set Light (x₁) 1.71 4.67 4.99 5.33 5.43 6.94 7.15 9.17 10.26 11.67 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: Select an answer ? V Select an answer V Ha: Select an answer ✓ Based on the hypotheses, find the following: Test Statistic = Dark (₂) 2.27 2.53 2.83 4 4.21 4.6 5.95 6.52 p-value = ? V Select an answer V (Hint: difference in means from Ha) The correct decision is to Select an answer…
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Please answer the question contained in the following picture
Earlier this semester, we learned to use 2-Sample-TTest to compare the population means of two independent populations. One-way ANOVA is more powerful because it could compare the population means of three or more independent populations. However, use of one-way ANOVA also requires the assumption that the populations have the same variance. In this exercise, we will compare and contrast One-way ANOVA and 2-Sample-TTest. With the 2-Sample- TTEST, we will first choose 'No' for the pooled variances option, then re-run the test while choosing 'Yes' for the pooled variances option. Use the following data to complete these tasks. Depending on if you choose to do this by hand or using code, use the data format that suits you best - LONG form on top or WIDE form on bottom. Treatment One One One One One One One Two Two Two Two Two Two Two Treatment One 7.1 8.5 7.6 7.7 6.9 8.5 7.8 Response 7.1 8.5 7.6 7.7 6.9 8.5 7.8 1.4 4.1 4.3 3.9 4 4 4.6 p-value= Treatment Two 1.4 4.1 4.3 3.9 4 4 4.6 1. Use…
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Which of the following conclusions is correct for these test results? > bartlett.test(len~river, data=rivers) Bartlett test of homogeneity of variances data: len by river Bartlett's K-squared = 0.61394, df = 4, p-value = 0.5226 %3D Hint* the first line of code should tell you the type of test you are dealing with. There is NO significant difference in variances among the rivers. There is a significant difference in variances among the rivers. There is NO significant difference in means among the rivers.

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A It is the assumption that the variances for levels of a repeated-measu B It is tested using Mauchly's test in SPSS. C D It is automatically met when a variable has only two levels. It is not assumed by multivariate tests.