How would Interpret the following data using two sample t-testing if unequal variances? Each of these columns of data represent a different soda bottling line, with the values representing the amount of soda per bottle in ounces. The business question being asked for each of the three comparisons is "do the two bottling lines bottle the same volume of soda on average, bearing in mind that the sample difference that you may observe could just be coincidence."Need help intrepreting Data using excel :Change number to 11 decimal places for correct intrepretation of data t-Test: Two-Sample Assuming Unequal Variances C7C3Mean20.0167949987020.19595999995Variance0.010324799770.06511791311Observations50.0000000000080.00000000000Hypothesized Mean Difference0.00000000000 df112.00000000000 t Stat5.60858201974 P(T<=t) one-tail0.00000007449 t Critical one-tail1.65857262879 P(T<=t) two-tail0.00000014898 t Critical two-tail1.98137181488 Two Tail P and t -(Excel)Two -Sample Assuming UnEqual Variances (Excel)Need difference between means Est. Error difference Degree of freedomHypothesisNull HypothesisAternative Hypothesis P value 0.05 (alpha )Is it significant ?

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Description: How would Interpret the following data using two sample t-testing if unequal variances? Each of these columns of data represent a different soda bottling line, with the values representing the amount of soda per bottle in ounces. The business questi

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How would Interpret the following data using two sample t-testing if unequal variances? Each of these columns of data represent a different soda bottling line, with the values representing the amount of soda per bottle in ounces. The business question being asked for each of the three comparisons is "do the two bottling lines bottle the same volume of soda on average, bearing in mind that the sample difference that you may observe could just be coincidence."

Need help intrepreting Data using excel :

Change number to 11 decimal places for correct intrepretation of data

t-Test: Two-Sample Assuming Unequal Variances

	C7	C3
Mean	20.01679499870	20.19595999995
Variance	0.01032479977	0.06511791311
Observations	50.00000000000	80.00000000000
Hypothesized Mean Difference	0.00000000000
df	112.00000000000
t Stat	5.60858201974
P(T<=t) one-tail	0.00000007449
t Critical one-tail	1.65857262879
P(T<=t) two-tail	0.00000014898
t Critical two-tail	1.98137181488

Two Tail P and t -(Excel)

Two -Sample Assuming UnEqual Variances (Excel)

Need difference between means

Est. Error difference

Degree of freedom

Hypothesis

Null Hypothesis

Aternative Hypothesis

P value

0.05 (alpha )

Is it significant ?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Step 1

From the given Excel output, the t test statistic is 5.6086 and the p-value for the two tail is 0.00000.

Estimated mean difference:0

Degrees of freedom:112

Null hypothesis:

H₀: µ₁=µ₂.

That is, two means are not significant.

Alternative hypothesis:

H₁: µ₁≠µ₂.

That is, two means are significant.

p-vallue:0.0000

alpha=0.05

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