A hoop of mass M = 3.50 kilograms (kg) and radius R = 12.5 centimeters (cm) is resting on a flat surface. There is a constant, horizontal force with a magnitude F = 2.75 Newtons (N) acting at the center of mass of the hoop. As a result, the hoop begins to roll without slipping. The moment of inertia of a hoop is given by I = MR². Find the resulting linear acceleration of the hoop, in units of meters per second squared (m/s²). см X-

icon
Related questions
Question
A hoop of mass M= 3.50 kilograms (kg) and radius R = 12.5 centimeters (cm) is resting
on a flat surface. There is a constant, horizontal force with a magnitude F = 2.75 Newtons
(N) acting at the center of mass of the hoop. As a result, the hoop begins to roll without
slipping. The moment of inertia of a hoop is given by I = MR². Find the resulting linear
acceleration of the hoop, in units of meters per second squared (m/s²).
см
X-
Transcribed Image Text:A hoop of mass M= 3.50 kilograms (kg) and radius R = 12.5 centimeters (cm) is resting on a flat surface. There is a constant, horizontal force with a magnitude F = 2.75 Newtons (N) acting at the center of mass of the hoop. As a result, the hoop begins to roll without slipping. The moment of inertia of a hoop is given by I = MR². Find the resulting linear acceleration of the hoop, in units of meters per second squared (m/s²). см X-
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer