phpvtSCCy.bin A homogeneous wire is bent into theshape shown. Determine, by directintegration, the centroid of the wire.Hint:[√P = ² dx = √√√² 2²³ 2²[√V₁²³ ± a ²³ dx = ³√(x²³ ± a ²¹P² + c[x²√x² = @²dx = ²√(x² ± a ²)² = ² xVx² = a ²af+ √x² + a²) |8In (x + √x² = a³) + C-1y=kx²X

Given Data:- Profile Y=KX2 To Find :- Centroid of the profile

A homogeneous wire is bent into the shape shown. Determine, by direct integration, the centroid of the wire. Hint: ● √ √²²=²&x= [√√²² =² = ²m (x + √²² =2) + C [VF² = ²³ dx = ²√(x² = a)³ +C [xVPz³d = {√@T@P = √² 4 -In (x + √x² ± a ²) + C ∙1 y=kx²

A homogeneous wire is bent into the shape shown. Determine, by direct integration, the centroid of the wire. Hint: ● √ √²²=²&x= [√√²² =² = ²m (x + √²² =2) + C [VF² = ²³ dx = ²√(x² = a)³ +C [xVPz³d = {√@T@P = √² 4 -In (x + √x² ± a ²) + C ∙1 y=kx²

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Center of Gravity and Centroid

The term center of gravity indicates the position or location of a point about which the whole weight of a body or system is supposed to be concentrated, which means the whole weight of the body or system works through this point. It is closely related to mass distribution. For all positions of the body, the center of gravity would be a single point.

Question

phpvtSCCy.bin

A homogeneous wire is bent into the
shape shown. Determine, by direct
integration, the centroid of the wire.
Hint:
[√P = ² dx = √√√² 2²³ 2²
[√V₁²³ ± a ²³ dx = ³√(x²³ ± a ²¹P² + c
[x²√x² = @²dx = ²√(x² ± a ²)² = ² xVx² = a ²
af
+ √x² + a²) |
8
In (x + √x² = a³) + C
-1
y=kx²
X

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