A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (orpivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distanced = 0.255 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight.If the homeowner can apply a maximum force of 655 N at the other end of the rod, what is the minimum total length L ofthe rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock andhomeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s².L =m

The mass of the rock, m = 325 kg The maximum force the homeowner can apply, Fo= 655 N The…

A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.255 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight. p - If the homeowner can apply a maximum force of 655 N at the other end of the rod, what is the minimum total length L of the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². L =

A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.255 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight. p - If the homeowner can apply a maximum force of 655 N at the other end of the rod, what is the minimum total length L of the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². L =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Rotational Equilibrium And Rotational Dynamics

In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.

Equilibrium of Forces

The tension created on one body during push or pull is known as force.

Question

A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or
pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance
d = 0.255 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight.
If the homeowner can apply a maximum force of 655 N at the other end of the rod, what is the minimum total length L of
the rod required to move the rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and
homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s².
L =
m

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