A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.200 m from the rock, which has a mass of 525 kg, and fits one end of the rod under the rock's center of weight. If the homeowner can apply a maximum force of 711 N at the other end of the rod, what is the minimum total length L of the rod required to moveſthe rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². m L =

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot
point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance
d = 0.200 m from the rock, which has a mass of 525 kg, and fits one end of the rod under the rock's center of weight.
%3D
If the homeowner can apply a maximum force of 711 N at the other end of the rod, what is the minimum total length L of
the rod required to moveſthe rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and
homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s².
m
L =
Transcribed Image Text:A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance d = 0.200 m from the rock, which has a mass of 525 kg, and fits one end of the rod under the rock's center of weight. %3D If the homeowner can apply a maximum force of 711 N at the other end of the rod, what is the minimum total length L of the rod required to moveſthe rock? Assume that the rod is massless and nearly horizontal so that the weight of the rock and homeowner's force are both essentially vertical. The acceleration due to gravity is g = 9.81 m/s². m L =
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