A hollow, thin-walled sphere of mass 12.0 kg and diameter 48.0 cm is rotating about an axle through its center. The angle (in radians) through which it turns as a function of time (in seconds) is given by 0(t) = At² + Bt4, where A has numerical value 1.50 and B has numerical value 1.10. 10. At the time 3.00 s, what is the angular momentum of the sphere? A. 357.16 kg m²/s B. 118.3 kg m²/s C. 211.7 kg m²/s D. 235.6 kg m²/s

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Chapter1: Units, Trigonometry. And Vectors
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A hollow, thin-walled sphere of mass 12.0 kg and diameter 48.0 cm is
rotating about an axle through its center. The angle (in radians) through which it turns as a
function of time (in seconds) is given by 0(t) = At² + Bt4, where A has numerical value 1.50
and B has numerical value 1.10.
10. At the time 3.00 s, what is the angular momentum of the sphere?
A. 357.16 kg m²/s
B. 118.3 kg m²/s
C. 211.7 kg m²/s
D. 235.6 kg m²/s
Transcribed Image Text:A hollow, thin-walled sphere of mass 12.0 kg and diameter 48.0 cm is rotating about an axle through its center. The angle (in radians) through which it turns as a function of time (in seconds) is given by 0(t) = At² + Bt4, where A has numerical value 1.50 and B has numerical value 1.10. 10. At the time 3.00 s, what is the angular momentum of the sphere? A. 357.16 kg m²/s B. 118.3 kg m²/s C. 211.7 kg m²/s D. 235.6 kg m²/s
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