Consider a spacecraft orbiting Earth. At an instant in time, the angular velocity of the spacecraft relative to Earth is - 1.961 +0.82bz+0.34ôz (in rad/s) and the angular acceleration of the spacecraft relative to Earth is ä = 0.0561 +0.19b2+0.22bg (in rad/s). What is the moment (in N.m) being applied on the spacecraft in the by. Assume the moment of inertia of the spacecraft is given by: Г5000 [I° = 0.0 0.0 0.0 10000 0.0 kg.m? 0.0 13000 Note b1, b2, bz are unit vectors fixed in the spacecraft reference frame.
Q: At the instant of the figure, a 1.6 kg particle P has a position vector of magnitude 1.7 m and angle…
A:
Q: Two skaters, each with a mass of 80 kg, are skating on opposite sides around a circle of radius 11…
A: Scenario - Two skaters of same mass are connected by a massless string and rotating opposite each…
Q: Now we have a rod-shaped space station of length 1017 m and mass 5.55 x 10^6 kg, which can change…
A:
Q: An ice skater is spinning at 5.6 rev/s and has a moment of inertia of 0.56 kg ⋅ m2. 1. Calculate…
A:
Q: A particle of mass 6.2 kg has position vector r = (1.9î – 3.4j) m at a particular instant of time…
A: Given Data:- Mass of the particle is m=6.2 kg Position vector of the particle is r→=1.9i^-3.4j^ m…
Q: Now we have a rod-shaped space station of length 1488 m and mass 7.87 x 10^6 kg, which can change…
A:
Q: Now we have a rod-shaped space station of length 1160 m and mass 7.69 x 10^6 kg, which can change…
A:
Q: Consider a spacecraft orbiting Earth. At an instant in time, the angular velocity of the spacecraft…
A: Given, The angular velocity of spacecraft with respect to earth is, ω→=1.6b^1+0.52b^2+0.21b^3 rad/s…
Q: A metal bar, weighing 2 kg with a length of 2 meters, freely spins around one of its extremities.…
A: Since you have not mentioned the point at which the moment of force have to be measured. Therefore,…
Q: A child sits on a merry‑go‑round that has a diameter of 4.00 m. The child uses her legs to push the…
A: Given: Diameter (d) = 4 m Angular speed (wf) = 16 rpm time (t) = 42…
Q: Now we have a rod-shaped space station of length 682 m and mass 4.04 x 10^6 kg, which can change its…
A: Initial length of the space station, l1=682 m Mass of the space station, m=4.04×106 kg (mass of…
Q: The blades of a ceiling fan have a radius of 0.389 m and are rotating about a fixed axis with an…
A: The angular acceleration of the blade α=2.95 rad/s2 The radius of the fan r=0.389 m The initial…
Q: A small particle of mass 0.82 kg is being whirled in a horizontal circle at the end of a 1.2 m long…
A:
Q: Consider a spacecraft orbiting Earth. At an instant in time, the angular velocity of the spacecraft…
A:
Q: You are looking down on a disc that is spinning counterclockwise in the xy plane (positive z points…
A:
Q: 60. A uniform rod of mass 200 g and length 100 cm is free to rotate in a horizontal plane around a…
A: We have given
Q: A child with a mass of 40 kg is riding on a merry-go-round. If the child has a speed of 3 m/s and is…
A:
Q: 10) Which vectors in graph below are equal? to too
A: Solution: Equal Vectors: If two vectors A and B are said to be equal if they have same…
Q: A playground merry-go-round, with radius 2.0 m and moment of inertia 51 kg m2, rotates with an…
A: The rotational analog of linear momentum is called angular momentum and is given as:L=Iωwhere I is…
Q: What is the angular momentum (in kg*m*m/s) of a 350 g symmetrical rotating bar which is 4.50 m long…
A: Given, Mass of symmetrical bar (m) = 0.350kg Length of bar (L) = 4.50m Bar is rotating about…
Q: A meter stick is hinged at its lower end and allowed to fall from a vertical position. If its moment…
A: Given: Moment of inertia I=ML2/3
Q: An ice skater is spinning at 6.8 rev/s and has a moment of inertia of 0.24 kg ⋅ m2. a)Calculate the…
A: Write the given values of this problem. I=0.24 kg.m2ωo=6.8 rev/sor, ωo=6.8 rev/s2πrad/srev/sωo=42.7…
Q: A rod with length L and mass M hangs vertically on a frictionless, horizontal axel passing through…
A:
Q: A star spins one revolution every 10 days and its radius is 7.00*105 km. It then collapses and…
A:
Q: You observe a 2 kg sphere with a position of 7 = (5i + 2j – 3k)m and a velocity of i = (2i + 5k) m/s…
A: Given data, Sphere mass m= 2kg Position r = 5i+2j-3k Velocity v= 2i + 5k And now we find angular…
Q: We have a rod-shaped space station of length 548 m and mass 4.19 x 10^6 kg, which can change its…
A:
Q: A 200 g puck revolves in a circle on a frictionless table at the end of a 50.0 cm long string. The…
A: Consider the mass of the puck be m, the angular momentum of the puck be L, the radius of the circle…
Q: Now we have a rod-shaped space station of length 1282 m and mass 7.89 x 10^6 kg, which can change…
A: Given Data: Length (L1) = 1282 m.Mass (m) = 7.89×106 kg.Initial rate of rotation (ω1) = 2.90…
Q: An ice skater is spinning at 6.4 rev/s and has a moment of inertia of 0.48 kg ⋅ m2. Calculate the…
A:
Q: The angular momentum of a sphere is given by L = (−5.00t3) + (6.10 − 1.80t2) + (6.95t), where L…
A:
Q: A playground merry-go-round with a mass of 105 kg and a radius of 1.5 m is rotating with an angular…
A: Given: The mass of the marry-go-round m1 = 105 kg. The mass of the child m2 = 17 kg. The radius of…
Q: A disk is mounted with its axis vertically. It has radius R and mass M. It is initially at rest. A…
A:
Q: If M1=180 Ib.ft, M2=90 lb.ft and M3=120 Ib.ft, determine the magnitude and coordinate direction…
A: Given data: M1=180 lb.ft M2=90 lb.ft M3=120 lb.ft Need to determine the resultant moment and its…
Q: We have a rod-shaped space station of length 687m and mass 5.35 x 10^6 kg, which can change its…
A:
Step by step
Solved in 2 steps with 2 images
- Find the angular momentum (in kg · m2/s) of Saturn in its orbit around the Sun. - The mass of Saturn is 5.680 ✕ 1026 kg, the orbital radius is 1.427 ✕ 109 km and the orbital period is 29.5 y. Compare this angular momentum with the angular momentum of Saturn on its axis. - The radius of Saturn is 6.027 ✕ 104 km and the rotation period is 10.66 h.A 1500-kg satellite orbits a planet in a circular orbit of radius 6.2 × 106 m. What is the angular momentum, in kg m2/s, of the satellite in its orbit around the planet if the satellite completes one orbit every 1.5 × 104 s?At latitude 30◦N the distance from the surface of the earth to the axis of rotation,r, is smaller than it is at the equator, by 13% (cos(30◦)≈0.87). If we assume that the angular momentum of a mass m(L=mrv) is conserved as the mass is moved from the equator to latitude 30◦N, how fast is its velocity,v, relative to the ground at 30◦N?
- A thin circular hoop made of tungsten is rotating about its axis.Two copper beads are gently attached to the opposite ends of adiameter of the tungsten hoop. Mass of tungsten hoop is m.Mass of each copper bead is M. The angular velocitiesbefore and after attachment of the copper beads are ω and ω',respectively. Find the final angular velocity ω'. (a)ω(m+2M)/m (b)ω(m-2M)/(m+2M) (c)ωm/(2m+M) (d)ωm/(m+2M).A mass on the end of a 0.50 m long string is spun overhead with a velocity of 3.5 m/s. What is the angular velocity of the mass? 0.14 rad/sec 1.17 rad/sec 7.00 rad/sec 24.5 rad/sec t 9964a) What is the period of rotation of Venus in seconds? (The period of rotation of Venus in hours is 5,832.5 hr.) Answer in seconds (b)What is the angular velocity (in rad/s) of Venus? (Enter the magnitude.) Answer in rad/s (c) Given that Venus has a radius of 6.1 ✕ 106 m at its equator, what is the linear velocity (in m/s) at Venus's surface? (Enter the magnitude of the linear velocity at the equator.) Answer on m/s
- Four 100 g masses are mounted on a much lighter (assume massless) ring. The ring has a radius of 0.1 m. If the ring is to spin around an axis perpendicular to the plane of the ring and passing through its center, what is the moment of inertia? 0.004 kg m^2 0.04 kg m^2 0.001 kg m^2 0.01 kg m^2 0.002 kg m^2a) Calculate the angular momentum (in kg · m2/s) of Mercury in its orbit around the Sun. (The mass of Mercury is 3.300 ✕ 1023 kg, the orbital radius is 5.790 ✕ 107 km and the orbital period is 0.241 y.) kg · m2/s (b) Compare this angular momentum with the angular momentum of Mercury on its axis. (The radius of Mercury is 2.440 ✕ 103 km and the rotation period is 1408 h.) Lorbital Lrotation =Now we have a rod-shaped space station of length 1296 m and mass 1.43 x 10^6 kg, which can change its length (kind of like an old-fashioned telescope), without changing its overall mass. Suppose that the station is initially rotating at a constant rate of 1.83 rpm. If the length of the rod is reduced to 1.83 m, what will be the new rotation rate of the space station? 1. 3.01 rpm 6.27 rpm 3 3.76 rpm 4 9.41 rpm
- A bicycle is traveling north at 6.84 m/s. The mass of the wheel, 2.6 kg, is uniformly distributed along the rim(I=mr2), which has a radius of 17.89 cm. What are the magnitude(in kg m2/s) and direction of the angular momentum of the wheel about its axle?While placing a compact disc into a CD player, you notice a small chip on its edge. You attempt to play the CD anyway by placing the CD into the player's deck with the chip at ?0=15.2∘θ0=15.2∘ as measured from the +?+x‑axis. The CD begins to rotate with angular acceleration ?=2.31 rad/s2.α=2.31 rad/s2. If the CD has been spinning for ?=3.51 st=3.51 s and the disc has a radius of ?=6.00 cm,r=6.00 cm, what are the ?–?x–y coordinates of the chip after this time, assuming the center of the disc is located at (0.00,0.00)A playground merry-go-round, with radius 2.9 m and moment of inertia 127 kg m2, rotates with an angular speed 2.7 rad/s. A boy (mass 46 kg), initially at rest, hops onto the outer edge of the merry-go round. What is the new angular speed (in rad/s) just after the boy has jumped on?