A star spins one revolution every 10 days and its radius is 7.00*105 km. It then collapses and becomes a neutron star with a radius of 20.0 km. It also loses one half its mass during the collapse. ). What is the new revolutions /day? (The moment of inertia of a star is 2/5 mr²) O 3.13*108 rev/day O 3.20*108 rev/day O 3.32*108 rev/day 1.70*108 rev/day O 2.45*108 rev/day

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Chapter34: Frontiers Of Physics
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### Angular Momentum and Neutron Star Formation

In this educational example, we explore the fascinating dynamics of a star's collapse into a neutron star and how its rotational characteristics change due to conservation of angular momentum. 

#### Scenario:

- A star completes one revolution every 10 days.
- Initial radius: \(7.00 \times 10^5 \) km.
- The star collapses into a neutron star:
  - New radius: 20.0 km.
  - The star loses one half of its mass during the collapse.

#### Question:

**What is the new rate of revolutions per day?**  
(The moment of inertia of a star is given by \( \frac{2}{5} mr^2 \).)

#### Multiple Choice Options:

- \(3.13 \times 10^8 \) rev/day
- \(3.20 \times 10^8 \) rev/day
- \(3.32 \times 10^8 \) rev/day
- \(1.70 \times 10^8 \) rev/day
- \(2.45 \times 10^8 \) rev/day

#### Explanation:

To find the new revolutions per day, consider the conservation of angular momentum. Angular momentum \(L\) is conserved and is defined as \(L = I \omega\), where \(I\) is the moment of inertia and \(\omega\) is the angular velocity.

1. **Initial Moment of Inertia (\(I_{\text{initial}}\)):**
   \[
   I_{\text{initial}} = \frac{2}{5} m r_{\text{initial}}^2
   \]
   Given:
   - Initial radius \( r_{\text{initial}} = 7.00 \times 10^5 \) km.

2. **New Moment of Inertia (\(I_{\text{final}}\)):**
   \[
   I_{\text{final}} = \frac{2}{5} \left( \frac{m}{2} \right) r_{\text{final}}^2
   \]
   Given:
   - Final radius \( r_{\text{final}} = 20.0 \) km.
   - The mass is halved: \( \frac{m}{2} \).

3. **Calculate Initial Angular Velocity (\(\omega_{\text{initial}}\)):**
   - The period (\(T\
Transcribed Image Text:### Angular Momentum and Neutron Star Formation In this educational example, we explore the fascinating dynamics of a star's collapse into a neutron star and how its rotational characteristics change due to conservation of angular momentum. #### Scenario: - A star completes one revolution every 10 days. - Initial radius: \(7.00 \times 10^5 \) km. - The star collapses into a neutron star: - New radius: 20.0 km. - The star loses one half of its mass during the collapse. #### Question: **What is the new rate of revolutions per day?** (The moment of inertia of a star is given by \( \frac{2}{5} mr^2 \).) #### Multiple Choice Options: - \(3.13 \times 10^8 \) rev/day - \(3.20 \times 10^8 \) rev/day - \(3.32 \times 10^8 \) rev/day - \(1.70 \times 10^8 \) rev/day - \(2.45 \times 10^8 \) rev/day #### Explanation: To find the new revolutions per day, consider the conservation of angular momentum. Angular momentum \(L\) is conserved and is defined as \(L = I \omega\), where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. 1. **Initial Moment of Inertia (\(I_{\text{initial}}\)):** \[ I_{\text{initial}} = \frac{2}{5} m r_{\text{initial}}^2 \] Given: - Initial radius \( r_{\text{initial}} = 7.00 \times 10^5 \) km. 2. **New Moment of Inertia (\(I_{\text{final}}\)):** \[ I_{\text{final}} = \frac{2}{5} \left( \frac{m}{2} \right) r_{\text{final}}^2 \] Given: - Final radius \( r_{\text{final}} = 20.0 \) km. - The mass is halved: \( \frac{m}{2} \). 3. **Calculate Initial Angular Velocity (\(\omega_{\text{initial}}\)):** - The period (\(T\
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