A turntable s pins on a frictionless bearing. Its moment of inertia is 3.00 x 10 -2 kg m2. It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, Lafter = [factor] x Lpefore (Hint: Since it moves vertically the putty has initial angular momentum of zero.) O a. 1.22 b.0.820 O. 1.00 (no change) d. 1.20
A turntable s pins on a frictionless bearing. Its moment of inertia is 3.00 x 10 -2 kg m2. It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, Lafter = [factor] x Lpefore (Hint: Since it moves vertically the putty has initial angular momentum of zero.) O a. 1.22 b.0.820 O. 1.00 (no change) d. 1.20
Related questions
Question
![A turntable spins on a frictionless bearing. Its moment of inertia is \(3.00 \times 10^{-2} \, \text{kg} \cdot \text{m}^2\). It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, \(L_{\text{after}} = [\text{factor}] \times L_{\text{before}}\). (Hint: Since it moves vertically, the putty has initial angular momentum of zero.)
- a. 1.22
- b. 0.820
- c. 1.00 (no change)
- d. 1.20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2721ccf2-fbe1-4868-87fa-588e33d78a8e%2Fe3d5eeb9-cd39-49a3-837b-a25a88736865%2F53eiz4q_processed.png&w=3840&q=75)
Transcribed Image Text:A turntable spins on a frictionless bearing. Its moment of inertia is \(3.00 \times 10^{-2} \, \text{kg} \cdot \text{m}^2\). It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, \(L_{\text{after}} = [\text{factor}] \times L_{\text{before}}\). (Hint: Since it moves vertically, the putty has initial angular momentum of zero.)
- a. 1.22
- b. 0.820
- c. 1.00 (no change)
- d. 1.20
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
