A turntable s pins on a frictionless bearing. Its moment of inertia is 3.00 x 10 -2 kg m2. It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, Lafter = [factor] x Lpefore (Hint: Since it moves vertically the putty has initial angular momentum of zero.) O a. 1.22 b.0.820 O. 1.00 (no change) d. 1.20

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A turntable spins on a frictionless bearing. Its moment of inertia is \(3.00 \times 10^{-2} \, \text{kg} \cdot \text{m}^2\). It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, \(L_{\text{after}} = [\text{factor}] \times L_{\text{before}}\). (Hint: Since it moves vertically, the putty has initial angular momentum of zero.)

- a. 1.22
- b. 0.820
- c. 1.00 (no change)
- d. 1.20
Transcribed Image Text:A turntable spins on a frictionless bearing. Its moment of inertia is \(3.00 \times 10^{-2} \, \text{kg} \cdot \text{m}^2\). It initially rotates at 25.0 rev/min about an axis through its center. Then, a 0.6-kg ball of putty is dropped vertically onto the turntable. It lands and sticks at a point 0.10 m from the center. By what factor does this collision change the angular momentum of the system? That is, \(L_{\text{after}} = [\text{factor}] \times L_{\text{before}}\). (Hint: Since it moves vertically, the putty has initial angular momentum of zero.) - a. 1.22 - b. 0.820 - c. 1.00 (no change) - d. 1.20
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