A solid globe (mass m = 10 kg, radius r= 0.20 m) is spinning at a rate of 9.5 revolutions per second about an axis through its center of mass. What is the total moment of inertia of the globe? O 0.13 kgm2 O 0.2 kgm2 O 0.16 kgm2 O 0.4 kgm2

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**Problem Statement:**

A solid globe (mass m = 10 kg, radius r = 0.20 m) is spinning at a rate of 9.5 revolutions per second about an axis through its center of mass. What is the total moment of inertia of the globe?

**Options:**

- ⃝  0.13 kgm²
- ⃝  0.2 kgm²
- ⃝  0.16 kgm²
- ⃝  0.4 kgm²

**Explanation:** The moment of inertia (I) of a solid sphere rotating about an axis through its center can be calculated using the formula:

\[I = \frac{2}{5} m r^2\]

Where:
- \(m\) is the mass of the sphere (10 kg)
- \(r\) is the radius of the sphere (0.20 m)

Substitute the given values into the formula:

\[I = \frac{2}{5} \times 10 \, \text{kg} \times (0.20 \, \text{m})^2\]

Please provide detailed solution on the website for better understanding.

---

To include information about the spinning rate or further technical details, please elaborate on how the spinning rate would be relevant to angular momentum or kinetic energy but it's not directly altering the moment of inertia calculation.

There are no graphs or diagrams in the image that need to be explained.
Transcribed Image Text:**Problem Statement:** A solid globe (mass m = 10 kg, radius r = 0.20 m) is spinning at a rate of 9.5 revolutions per second about an axis through its center of mass. What is the total moment of inertia of the globe? **Options:** - ⃝ 0.13 kgm² - ⃝ 0.2 kgm² - ⃝ 0.16 kgm² - ⃝ 0.4 kgm² **Explanation:** The moment of inertia (I) of a solid sphere rotating about an axis through its center can be calculated using the formula: \[I = \frac{2}{5} m r^2\] Where: - \(m\) is the mass of the sphere (10 kg) - \(r\) is the radius of the sphere (0.20 m) Substitute the given values into the formula: \[I = \frac{2}{5} \times 10 \, \text{kg} \times (0.20 \, \text{m})^2\] Please provide detailed solution on the website for better understanding. --- To include information about the spinning rate or further technical details, please elaborate on how the spinning rate would be relevant to angular momentum or kinetic energy but it's not directly altering the moment of inertia calculation. There are no graphs or diagrams in the image that need to be explained.
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