A hollow aluminum shaft (see figure) has an outside diameter d,- 3.4 in. and inside diameter d, - 1.7 in. When twisted by torques T, the shaft has an angle of twist per unit distance equal to 0.46/ft. The shear modulus of elasticity of the aluminum is G = 4.0 x 10° psi. (a) Determine the maximum tensile stress amay in the shaft (in psi). (Enter the magnitude.) psi (b) Determine the magnitude of the applied torques T (in Ib - in.). Ib in.

A hollow aluminum shaft (see figure) has an outside diameter d,- 3.4 in. and inside diameter d, - 1.7 in. When twisted by torques T, the shaft has an angle of twist per unit distance equal to 0.46/ft. The shear modulus of elasticity of the aluminum is G = 4.0 x 10° psi. (a) Determine the maximum tensile stress amay in the shaft (in psi). (Enter the magnitude.) psi (b) Determine the magnitude of the applied torques T (in Ib - in.). Ib in.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A hollow aluminum tube used is a roof structure has an outside diameter d2=70mm and inside diameter d1= 50mm. The tube is 2.5m long and the aluminum has a shear modulus of G=28 GPa. a.) If the tube is twisted in pure torsion by torques acting at the ends, what is the angle of twist in degrees when the max shear stress is 50MPa? b.) What diameter 'd' is required for a solid shaft to resist the same torque with the same maximum stress?
A 3-m aluminum tube with the cross section shown carries a 200 N-m torque. Determine the following: a) the Maximum Shear Stress in the tube b) The relative angle of rotation of the ends of the tube. (For aluminum, use G = 28GPA) 100 mm 50 mm 2.4 mm 1.2 mm
A hollow steel shaft transmits 600 kW at 500 rpm. The maximum shear stress is 62.4 MPa. Find the outside and inside diameter of the shaft, if the outer diameter is twice of inside diameter, assuming that the maximum torque is 20% greater than the mean torque.
A shaft ABCD is supported by a clamp at point A and is subjected to point torques at B, C and D, as shown in the figure. The shaft has variable cross-section and is solid in segments AB and CD and hollow in segment BC. The lengths and diameters of each segment are shown in the figure. Assume that the deformation is linear elastic and take the shear modulus of elasticity G = 12.1 × 10° psi. a) Using method of sections, plot the torsion moment diagram. b) Find the angle of twist for the free end (point D) with respect to the fixed support at A, QAD and the angle of twist for point C with respect to the fixed support at A, QCA. Find both angles in degrees. d₁ = 4 in d20 3.5 in, d2=2.5 in d3 = 3.0 in 25 kip-in 20 kip-in 10 kip-in A 20 in B с D ++ 25 in 30 in
A 3.00 in-diameter steel shaft has a flat milled on one side as shown in the following figure. The shaft is 44.0 inch long and carries a torque of 10,600 lb∙in. Compute the maximum shear stress and the angle of twist for the shaft. The shear modulus G is 80 GPa
The shaft in Figure below consists of a 3-in. -diameter aluminum segment that is rigidly joined to a 2-in. -diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the maximum shear stress developed in each segment when the torque T= 10 kip.in is applied. Use G = 4×106 psi for aluminum and G = 12×106 psi for steel. Aluminum 3-in. diameter 6 ft T Steel 2-in. diameter 3 ft
H K T A solid shaft is subjected to forces and a torque as shown in figure. The diameter of the shaft is 35 mm, T=75 N.m., V=3 kN, P=4,7 kN and L=117 mm. Determine the shear stress (T) at point H (MPa). Note: If the stress has negative direction, use sign. Yanıt:
1: A stepped shaft ACB having a solid circular cross sections with two different diameters and two different materials joined and attached at their ends, in the fisrt section AC of aluminum has a diameter of 20mm lenght of 225mm and G= 28x109 N/m2 and in the second section CB of steel has a diameter of 25mm leght 450mm and G=83x109N/m2. The torque appied is of 1000N.m and applied in the joint of the pieces. Determine the shear stress in both the aluminium and the steel.
A hollow steel shafts transmits 200kW of power at 150 rpm. The total angle of twist in a length of 5 m of the shaft is 3Â°. Find the inner and outer diameter of the shaft. If the permissible shear stress is 60 MPa. Modulus of rigidity (C) =80 GPa
a A steel shaft of solid elliptical cross section has a semi-major axis of length, a, and a semi-minor axis of length, b, as shown in the accompanying figure. Given that a = 20 mm and b = 17 mm in this case, and given that the shear modulus of the steel is 80 GPa, calculate the angle of twist per unit length when a torque of 560 Nm is applied to the shaft. Enter your answer in units of radians/metre to 4 decimal places.
The compound shaft is attached to a rigid wall at each end. For the bronze segment AB, the diameter is 72 mm and G = 30.49 GPa. For the steel segment BC, the diameter is 48 mm and G = 83.57 GPa. Given that a = 2.09 m and b = 1.48 m, compute the largest torque T (in Nm) that can be applied as shown in the figure if the maximum shear stress is limited to 66.49 MPa in the bronze and 85.69 MPa in the steel. Round off the final answer to two decimal places.
The compound shaft is attached to a rigid wall at each end. For the bronze segment AB, the diameter is 70 mm and G = 33.29 GPa. For the steel segment BC, the diameter is 40 mm and G = 84.85 GPa. Given that a = 2.03 m and b = 1.38 m, compute the largest torque T (in Nm) that can be applied as shown in the figure if the maximum shear stress is limited to 64.59 MPa in the bronze and 84.39 MPa in the steel. Round off the final answer to two decimal places. d A Bronze B Steel b. Add your answer