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A hemispherical bowl has top radius 4 ft and at time t = 0 is full of water. At 1:00 P.M. a circular hole of unknown radius r is opened, and at 1:30 P.M. the depth of the water in the tank is 3 ft. (a) Use Torricelli's law in the form dV dt bottom hole? = - (0.6)πr² √/2gy to determine when the tank will be empty. (b) What is the radius of the (a) The tank will be empty after seconds. (Do not round until the final answer. Then round to the nearest second as needed.)

A hemispherical bowl has top radius 4 ft and at time t = 0 is full of water. At 1:00 P.M. a circular hole of unknown radius r is opened, and at 1:30 P.M. the depth of the water in the tank is 3 ft. (a) Use Torricelli's law in the form dV dt bottom hole? = - (0.6)πr² √/2gy to determine when the tank will be empty. (b) What is the radius of the (a) The tank will be empty after seconds. (Do not round until the final answer. Then round to the nearest second as needed.)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A hemispherical bowl has top radius 4 ft and at time t = 0 is full of water. At 1:00 P.M. a circular hole of unknown radius r is opened, and at 1:30 P.M. the depth of the water in the tank is 3 ft. (a) Use Torricelli's law in the form dV dt bottom hole? = - (0.6)πr² √/2gy to determine when the tank will be empty. (b) What is the radius of the (a) The tank will be empty after seconds. (Do not round until the final answer. Then round to the nearest second as needed.)
Transcribed Image Text:A hemispherical bowl has top radius 4 ft and at time t = 0 is full of water. At 1:00 P.M. a circular hole of unknown radius r is opened, and at 1:30 P.M. the depth of the water in the tank is 3 ft. (a) Use Torricelli's law in the form dV dt bottom hole? = - (0.6)πr² √/2gy to determine when the tank will be empty. (b) What is the radius of the (a) The tank will be empty after seconds. (Do not round until the final answer. Then round to the nearest second as needed.)
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