So dt = 1+14 A. B. C. 11/12 71 N|T (x²) arctan (x4) arctan ½ ln (1 + x ¹ )

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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t
So dt:
=
1+t²4
A.
B.
C.
D.
E.
½arctan (x²)
arctan (x4)
In (1+x¹)
-In
(1+2¹)
arcsin (x²)
Transcribed Image Text:t So dt: = 1+t²4 A. B. C. D. E. ½arctan (x²) arctan (x4) In (1+x¹) -In (1+2¹) arcsin (x²)
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