26) y = tan((T/6)x) Period: TT. -217 -ㅠ TT 21T -2 -1 -1 -2 -ㅠ MCL @01 %24 ElN-

Q: s dx ²√x² x² - 81 x² x = 9 sec (0)

A: ∫dxx2x2-81

Q: 3x+sinx-3 tan x -) Given g(x) = ln- calculate g'(x). %3D 3x4-Vx

A: Given gx=lnx3+sinx-3tanx3x4-x We know that lnab=lna-lnb. Therefore, using this formula we can write…

Q: sin² sin'x =-COSr 2. 0, 2.

A: To solve for x , where x should lie in the interval  [0,π/2]

Q: dx 5. S- (4x – x2)°/2

A: Note:- Since you have asked multiple question As per our policy, we will solve the first question…

Q: d -[x*] = xx"-1 dx

A:

Q: If a ball is thrown in the air with a velocity 48 ft/s, its height in feet t seconds later is given…

A:

Q: What is the instantaneous rate of change of the graph of y = = cos x when x= 2n?

A:

Q: 1. S(1+ tanx)?dx

A:

Q: Evaluate B f da where A = (x² - 1) and B = 22. You must show all steps.

A: Given data

Q: 1/x dx 3?

A:

Q: 106. y' = y² – %, Yı = 0 %3D

A:

Q: differntiate y= (lnx)^(cosx)^(sinx)

A:

Q: Ghana (a) GHC110.55/acre (e) None of the above on 29. It is estimated that r years fromn now, the…

A:

Q: csc[In(tan e4*)] CsC y = coth[In(1-x)1/3]

A:

Q: TER arccos(x)dx

A:

Q: fx- sin(2x ) dx

A: Given that  The integral is xsin(2x^2) To evaluate the integral

Q: ∫ln(x)/x dx

A: GIven : ∫ln(x)xdx

Q: u) sec(2-x)tan(2-x)dx

A: To evaluate ∫sec2-xtan2-xdx

Q: X = Ys e %3D (ras.t) %3D (2.1,0)

A: Here we have given u in terms of x,y,z and x,y,z in terms of r,s,t , We use above given relations to…

Q: 81 xp xV In(x)

A:

Q: olve: y=ln ln [cos2(3x)]

A:

Q: Cos(pi/6)=(150-(y^2))/10800

A:

Q: tan-1 (tanx)= x where..............

A: It is known that tan-1tanx=x for all values lies on -π2, π2.

Q: Solve S 1 (4x² - 9) ³/2 dx using trig sub and solve

A:

Q: Question: Which graph represents  y = -2/3x - 3

A: The given equation of line is  y = (- 2/3)x - 3