A GO= -240.6 kJ/mol at 25°C for the reaction with ALL species at standard conditions. 2 Ag* (aq) + Fe (s) → Fe2* (aq) + 2 Ag (s) Find the standard cell potential AND the equilibrium constant E° =1.25 K 1.5 x 1042 E° = 2.49 K 1.5 x 1042 E° = 0.00125 K 6.8 x 10-43 E° = 1.25 6.8 x 10-43 E° = 2.49 K = 1.3 x 1097 Eo and/or K aren't listed correctly among the other choices; include the correct values with your submitted work

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A GO= -240.6 kJ/mol at 25°C for the reaction with ALL species at standard
conditions. 2 Ag* (aq) + Fe (s) → Fe2* (aq) + 2 Ag (s)
Find the standard cell potential AND the equilibrium constant
E° =1.25
K = 1.5 x 1042
E° = 2.49
K = 1.5 x 1042
E° = 0.00125
K = 6.8 x 10-43
E° = 1.25
6.8 x 10-43
E° = 2.49
K = 1.3 x 1097
E, and/or K aren't listed correctly among the other choices; include the correct
values with your submitted work
Transcribed Image Text:A GO= -240.6 kJ/mol at 25°C for the reaction with ALL species at standard conditions. 2 Ag* (aq) + Fe (s) → Fe2* (aq) + 2 Ag (s) Find the standard cell potential AND the equilibrium constant E° =1.25 K = 1.5 x 1042 E° = 2.49 K = 1.5 x 1042 E° = 0.00125 K = 6.8 x 10-43 E° = 1.25 6.8 x 10-43 E° = 2.49 K = 1.3 x 1097 E, and/or K aren't listed correctly among the other choices; include the correct values with your submitted work
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