tebe laer. harasoflrglamriradipVICEling trm CallegCapialgh LELECTRONICFIGETING OnENAPPROPRIATE PHTSICALCONTACTPrac. Prob's FI18-224) feCly5) BizMolar MassAnnK2) 39.10+ 16.0 t1.0156.11 g/mol)P-30.92) CI: 51.99) Ca- 40 074) Ar: 1495) Na= 20.96) Al= 269H= 1012) Kott3) BeCla) CI = 2(35 45)= 0.91 g/molnote bookCH17) Dr na%3DExitticket: 1-18-aafrm1-1aned selveslom problem) Calculate the number oF COa mal in 3.00 molecules(I mole =(6 02 Y 10) Còa= 44.619)2) UF; 3) Soa 9) Hypy 5) (nH), SOy) CHy CootH3.00 X|- 10-2) nuc-1) malaerent SystPlanct +AndnaBoc55

3.Molar mass of BeCl2 Be mass = 9.012 g/mol Cl mass = 35.5g/mol BeCl2 = 9.012 + (2×35.5) =…

Answered: 10.91 9/mol 2) KOHH 3) BeCla )CI = a(35…

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Chemistry

10.91 9/mol 2) KOHH 3) BeCla )CI = a(35 45)= 0.91 g /mol 5) Big 2CF lir keti l-15-aa

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter3: Statistical Tests With Excel

Section: Chapter Questions

Problem 1P

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

tebe laer. harasof
lrglamriradip
VICE
ling trm Calleg
Capialgh L
ELECTRONIC
FIGETING On
ENAPPROPRIATE PHTSICAL
CONTACT
Prac. Prob's FI18-22
4) feCly
5) Biz
Molar Mass
Ann
K
2) 39.10+ 16.0 t1.01
56.11 g/mol
)P-30.9
2) CI: 51.99
) Ca- 40 07
4) Ar: 149
5) Na= 20.9
6) Al= 269
H= 101
2) Kott
3) BeCla
) CI = 2(35 45)= 0.91 g/mol
note book
CH
17) Dr na
%3D
Exit
ticket: 1-18-aa
frm
1-1
aned selve
slom problem
) Calculate the number oF COa mal in 3.00 molecules
(I mole =(6 02 Y 10) Còa= 44.619)
2) UF; 3) Soa 9) Hypy 5) (nH), SOy
) CHy CootH
3.00 X
|- 10-2
) nuc-
1) mala
erent Syst
Planct +Andna
Boc
55

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