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204.094. 2) How many N₂04 molecules are contained in 76.3 g N₂04? The molar mass of N204 is 92.02 g/mol. A) 5.54 x 1025 N2O4 molecules B) 7.26 x 1023 N₂O4 molecules C) 4.59 x 1025 N₂04 molecules D) 4.99 x 1023 N2O4 molecules E) 1.38 x 1024 N2O4 molecules

204.094. 2) How many N₂04 molecules are contained in 76.3 g N₂04? The molar mass of N204 is 92.02 g/mol. A) 5.54 x 1025 N2O4 molecules B) 7.26 x 1023 N₂O4 molecules C) 4.59 x 1025 N₂04 molecules D) 4.99 x 1023 N2O4 molecules E) 1.38 x 1024 N2O4 molecules

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A) 56.00 g/mol B) 139.99 g/mol C204.13 g/mol D) 86.03 g/mol E) 258.09 g/mol A) 5.54 x 1025 N₂O4 molecules B) 7.26 × 1023 N₂O4 molecules C) 4.59 x 1025 N₂O4 molecules D) 4.99 x 1023 N₂O4 molecules E) 1.38 x 1024 N₂O4 molecules C- 6x 12.011 = 72.066 H-D 9x 1.006 = 9.054 + 067 15.999 = 2) How many N₂04 molecules are contained in 76.3 g N204? The molar mass of N₂O4 is 92.02 g/mol. B) 6.39 kg 95.994 204.094-6204.1g/mol 3) What is the mass (in kg) of 6.89 x 1025 molecules of CO₂? The molar mass of CO2 is 44.01 g/mol. E) 3.85 kg A) 2.60 kg C) 5.04 kg D) 3.03 kg 4) Write a balanced equation to show the reaction of aqueous aluminum acetate with aqueous ammonium phosphate to form solid aluminum phosphate and aqueous ammonium acetate. A) Al(C₂H3O2)2 (aq) + (NH3)2PO4 (aq) AlPO4 (s) + 2NH3C₂H3O3(aq) B) Al(C₂H3O2)3 (aq) + (NH4)3PO4 (aq) → AlPO4 (s) + 3 NH4C2H303 (aq) C) A1(CO₂)3 (aq) + (NH4)3PO3 (aq) → AIPO3 (s) +3 NH4CO₂ (aq) D) Al(C₂H302)2 (aq) + (NH4)2PO4 (aq) → AIPO4 (s) +2 NH4C₂H303 (aq) E) Al(CO3)2 (aq) + (NH3)2PO4 (aq) → AIPO4 (s) +2 NH3CO3 (aq) 2) moles of NO are formed from 8.44 3) _ 4) 5)
Transcribed Image Text:A) 56.00 g/mol B) 139.99 g/mol C204.13 g/mol D) 86.03 g/mol E) 258.09 g/mol A) 5.54 x 1025 N₂O4 molecules B) 7.26 × 1023 N₂O4 molecules C) 4.59 x 1025 N₂O4 molecules D) 4.99 x 1023 N₂O4 molecules E) 1.38 x 1024 N₂O4 molecules C- 6x 12.011 = 72.066 H-D 9x 1.006 = 9.054 + 067 15.999 = 2) How many N₂04 molecules are contained in 76.3 g N204? The molar mass of N₂O4 is 92.02 g/mol. B) 6.39 kg 95.994 204.094-6204.1g/mol 3) What is the mass (in kg) of 6.89 x 1025 molecules of CO₂? The molar mass of CO2 is 44.01 g/mol. E) 3.85 kg A) 2.60 kg C) 5.04 kg D) 3.03 kg 4) Write a balanced equation to show the reaction of aqueous aluminum acetate with aqueous ammonium phosphate to form solid aluminum phosphate and aqueous ammonium acetate. A) Al(C₂H3O2)2 (aq) + (NH3)2PO4 (aq) AlPO4 (s) + 2NH3C₂H3O3(aq) B) Al(C₂H3O2)3 (aq) + (NH4)3PO4 (aq) → AlPO4 (s) + 3 NH4C2H303 (aq) C) A1(CO₂)3 (aq) + (NH4)3PO3 (aq) → AIPO3 (s) +3 NH4CO₂ (aq) D) Al(C₂H302)2 (aq) + (NH4)2PO4 (aq) → AIPO4 (s) +2 NH4C₂H303 (aq) E) Al(CO3)2 (aq) + (NH3)2PO4 (aq) → AIPO4 (s) +2 NH3CO3 (aq) 2) moles of NO are formed from 8.44 3) _ 4) 5)
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