(a) Given that X is normally distributed with mean 10 and P(X > 12) = 0.1587. What is the probability that X will fall in the interval (9, 11)? You are given; (1) = 0.8413 and +(-;)= 0.3085, where (z) = P(-∞< Z < z)such that Z~N(0,1).

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(a) Given that X is normally distributed with mean 10 and P(X > 12) :
0.1587. What is the probability that X will fall in the interval (9, 11)? You
are given; (1) = 0.8413 and +(-;) = 0.3085, where (z) =
P(-0 < Z < z)such that Z~N(0,1).
%3D
Transcribed Image Text:(a) Given that X is normally distributed with mean 10 and P(X > 12) : 0.1587. What is the probability that X will fall in the interval (9, 11)? You are given; (1) = 0.8413 and +(-;) = 0.3085, where (z) = P(-0 < Z < z)such that Z~N(0,1). %3D
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