The pdf of the time to failure of an electronic component in a copier (in hours) is f (x) = [exp (-x/3100)]/3100 for x > 0 and f (x) = 0 for x ≤ 0. Determine the probability that: (a) A component lasts more than 1180 hours before failure. (b) A component fails in the interval from 1180 to 2010 hours. (c) A component fails before 3010 hours. (d) Determine the number of hours at which 11% of all components have failed. (e) Determine the mean. Round your answers to three decimal places (e.g. 98.765).
The pdf of the time to failure of an electronic component in a copier (in hours) is f (x) = [exp (-x/3100)]/3100 for x > 0 and f (x) = 0 for x ≤ 0. Determine the probability that: (a) A component lasts more than 1180 hours before failure. (b) A component fails in the interval from 1180 to 2010 hours. (c) A component fails before 3010 hours. (d) Determine the number of hours at which 11% of all components have failed. (e) Determine the mean. Round your answers to three decimal places (e.g. 98.765).
The pdf of the time to failure of an electronic component in a copier (in hours) is f (x) = [exp (-x/3100)]/3100 for x > 0 and f (x) = 0 for x ≤ 0. Determine the probability that: (a) A component lasts more than 1180 hours before failure. (b) A component fails in the interval from 1180 to 2010 hours. (c) A component fails before 3010 hours. (d) Determine the number of hours at which 11% of all components have failed. (e) Determine the mean. Round your answers to three decimal places (e.g. 98.765).
The pdf of the time to failure of an electronic component in a copier (in hours) is f (x) = [exp (-x/3100)]/3100 for x > 0 and f (x) = 0 for x ≤ 0. Determine the probability that:
(a) A component lasts more than 1180 hours before failure. (b) A component fails in the interval from 1180 to 2010 hours. (c) A component fails before 3010 hours. (d) Determine the number of hours at which 11% of all components have failed. (e) Determine the mean.
Round your answers to three decimal places (e.g. 98.765).
Definition Definition Probability of occurrence of a continuous random variable within a specified range. When the value of a random variable, Y, is evaluated at a point Y=y, then the probability distribution function gives the probability that Y will take a value less than or equal to y. The probability distribution function formula for random Variable Y following the normal distribution is: F(y) = P (Y ≤ y) The value of probability distribution function for random variable lies between 0 and 1.
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